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finlep [7]
2 years ago
11

Jason is designing the packaging for a new brand of snack crackers. To fit on shelves, the package must not be more than 8 1/2 i

nches tall. The company wants the base of the package to be squared so that it stands out of its competitors. The box must be able to hold 100 cubic units of crackers. Which could be the dimensions for Jason's design?
Mathematics
1 answer:
drek231 [11]2 years ago
6 0

Answer:

Step-by-step explanation:

8 1/2 inches  = \frac{17}{2} inches

To fit on shelves, the package must not be more than 8 1/2 inches tall, it means the height of the package can be at \frac{17}{2} inches

The box must be able to hold 100 cubic units of crackers. it means the volume of the box is 100 cubic units.

The base of the package to be squared

And we have the formula:

V = h*S (Area of the base)

=> S = V/h = 100 :  \frac{17}{2} = \frac{200}{17}  

=> the side of square: \sqrt{\frac{200}{17} }

The dimensions for Jason's design are:

The height: \frac{17}{2} inches  

The length and width: \sqrt{\frac{200}{17} }

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Answer:

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Step-by-step explanation:

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2 years ago
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Solve for z a(t+z)=45z+67
ladessa [460]
Solve for z a(t+z)=45z+67
1. Expand
at+az=45z+67

2. Subtract at from both sides
az=45z+67-at

3. Subtract 45z from both sides
az-45z=67-at

4. Factor out the common term z
z(a-45)=67-at

5. Divide both sides by a - 45
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2 years ago
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Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production
Whitepunk [10]

Answer:

32% probability of a defect.

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Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

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95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 10

Standard deviation = 0.15.

Probability of a defect

Weights less than 9.85 oz or greater than 10.15 oz will be classified as defects.

9.85 = 10 - 0.15

10.15 = 10 + 0.15

By the Empirical Rule, 68% of weights are between 9.85 and 10.15, that is, within the limits. 32% are not within the limits.

So there is a 32% probability of a defect.

Expected number of defects for a 1000-unit production run.

E(X) = 0.32*1000 = 320

The expected number of defects for a 1000-unit production run is 320.

5 0
2 years ago
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Ulleksa [173]
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Therefore, the factorization of the number 2*2*2*4*5 can be broken down to 2*2*2*2*2*5.
3 0
2 years ago
The winners of a carnival game draw a ticket from a box to determine their prize. Each winner draws a ticket and places it back
swat32

Answer:

He generates a random whole number from 1 to 3.

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