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SCORPION-xisa [38]
2 years ago
10

Two parallel lines are crossed by a transversal. Parallel lines r and s are cut by transversal q. On line s where it intersects

with line q, the uppercase left angle is 125 degrees and the bottom right angle is d degrees. What is the value of d? d = 55 d = 75 d = 125 d = 155

Mathematics
2 answers:
mojhsa [17]2 years ago
8 0

Answer:

D)155

Step-by-step explanation:

Just took test today and got it right :) hope this helped

8_murik_8 [283]2 years ago
6 0

Answer:

The value of d is 55

Step-by-step explanation:

Given:

r and s are two parallel lines

q is the Transversal

uppercase left angle is 125 degrees

The bottom right angle is d degrees

To Find:

The value of d = ?

Solution:

We know that the sum of supplementary angles is 180^{\circ}

Refer the diagram below,

Now

125^{\circ} +( x )= 180^{\circ}

( x )= 180^{\circ}-125^{\circ}

( x )= 55^{\circ}

Also we know that

Alternate interior angles are formed by a transversal intersecting two parallel lines . They are located between the two parallel lines but on opposite sides of the transversal, creating two pairs (four total angles) of alternate interior angles. Alternate interior angles are congruent, meaning they have equal measure.

So d  will also be 55^{\circ}

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If Line segment C B. bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three option
meriva

Answer:

Option (1)

Step-by-step explanation:

In the figure attached,

BC is the angle bisector of angle ACD.

To prove ΔABC and ΔDBC congruent by SAS property we require two sides and the angle between these sides to be congruent.

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Both the triangles will be congruent.

Therefore, additional information required to prove ΔABC ≅ ΔDBC have been given in option (1).

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Answer:

Step-by-step explanation:

The given quadratic equation is

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x = [- 3 ± √3^2 - 4(2 × -8)]/2×2

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Step-by-step explanation:

Credit line - $8,000.00

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