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2 years ago

If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs

Mathematics

1 answer:

sammy [17]2 years ago

6 0

Answer:

$QS=68\ units$

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

$8x-43=(2x-4)+(4x-1)$

$8x-43=6x-5$

$8x-6x=43-5$

$2x=38$

$x=19$

step 2

Find the value of RS

$RS=2x-4$

substitute the value of x

$RS=2(19)-4$

$RS=34\ units$

step 3

Find the value of QS

Remember equation A

QS=2RS

$QS=2(34)=68\ units$

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andrey2020 [161]

Answer:

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Part 4) The information not used for the equation is that the plane was travelling for 4 hours to cover 1800 miles before starting the descent

Step-by-step explanation:

Part 1)

The rate at which the airplane descends is given by the difference between final and initial altitude (17,000 ft-33,000 ft) divided the elapsed time (8 minutes):

$Descending\,\,Rate\,= \frac{17000-33000}{8} \,\,\frac{ft}{min}=\frac{-16000}{8} \,\,\frac{ft}{min}=-\,2000\,\,\frac{ft}{min}$

Part 2)

When graphing the descent (that is the plane's altitude as a function of time), the starting value for the altitude should be 33,000 ft

Part 3)

We can build the equation of the plane's altitude as a function of time in slope y-intercept form y = m x + b

by noticing that the slope "m" stands for the rate of descent that we found in part 1), and then using the information that at time zero (when the plane starts its descent), its altitude is 33000 ft:

$y=m\,x\,+\,b\\y=-2000\,\frac{ft}{min} \,x\,+\,b\\33000=-2000\,\frac{ft}{min} \,(0)\,+\,b\\33000=b$

with this information about the intercept "b", we can write the final expression for the plane's altitude as a function of time during its descent as:

$y=-2000\,\frac{ft}{min} \,x\,+\,33000\,ft$

Part 4)

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