Answer:
I think your functions are 
,
and 
If yes then then the third function which is .
Step-by-step explanation:
The function 
where c is a constant has
Domain : 
Range : ( 0 , ∞ )
The above range is irrespective of the value of c.
I have attached the graph of each of the function, you can look at it for visualization.
- <em> ⇒ </em>This function is same as so its range is <em>( 0 , ∞ )</em>.
- <em> ⇒ </em>If we double each value of the function
, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as <em>( 0 , ∞ )</em>.
- <em></em> ⇒ If we add 2 to each value of the function , which has range ( 0 , ∞ ), the lower limit will change as 0+2=2 but the upper limit will be same as ∞. Therefore the range will become as <em>( 2 , ∞ )</em>.
< CAD = 100....if u add < ACB + < CBA u get < CAD
================
< DAB = 125 and < ACB = 30
if DAB = 125.....then BAC = 180 - 125 = 55
and all 3 interior angles of a triangle = 180
< BAC + < ACB + < ABC = 180
55 + 30 + < ABC = 180
85 + < ABC = 180
< ABC = 180 - 85
< ABC = 95 <===
Addends are any of the numbers added together in an equation.
The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations.
For ex:
2 - (8 + 3) here, the 8 and 3 have to be grouped together before doing the subtraction.
Any addition problem without parentheses can be used for one where the grouping doesn't matter
The conversion rate US dollars to Euros is represented with the function:
E(n)=0.72n
n- number of dollars
E(n) - Euros as a function of US dollars
The conversion rate Euros to Dirhams is :
D(x)=5.10x
x- number of Euros
D(x)- Dirhams as a function of Euros
<span>We are trying to find D(x) in terms of n.
D(x) = 5.10x
x can be rewritten as E(n)
D(x) = 5.10(E(n))
D(x) = 5.10(E(n))
D(x) = 5.10(0.72n)
D(x) = 3.672n </span>
According to this the following statement is true:
A) <span>(D x E)(n) = 5.10(0.72n)</span>
