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viktelen [127]
2 years ago
9

lorenzo rides his bike at a rate of 5 yards per second. about how many miles per hour can lorenzo ride his bike

Mathematics
1 answer:
VladimirAG [237]2 years ago
5 0
Can you send the answer choices?
You might be interested in
Triangle J K L is shown. Angle K L J is a right angle. The length of hypotenuse K J is 10.9 centimeters and the length of L J is
scZoUnD [109]

Answer:

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

Step-by-step explanation:

From the given triangle JKL;

Hypotenuse KJ = 10.9

Length LJ is the opposite = 8.9cm

The angle LKJ is the angle opposite to side KJ = x

Using the SOH CAH TOA Identity;

sin theta = opp/hyp

sin LKJ = LJ/KJ

Sinx = 8.9/10.9

x = arcsin(8.9/10.9)

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

7 0
2 years ago
Read 2 more answers
James has a desk job and would like to become more fit, so he purchases a tread walker and a standing desk which will allow him
Hitman42 [59]

Answer:

answer is

-0.245 \pm2.160(0.205)

Step-by-step explanation:

After working this way for 6 months he takes a simple random sample of 15 days. He records how long he walked that day (in hours) as recorded by his fitness watch as well as his billable hours for that day as recorded by a work app on his computer.

Slope is -0.245

Sample size  n = 15

Standard error is 0.205

Confidence level 95

Sognificance level is (100 - 95)% = 0.05

Degree of freedom is n -2 = 15 -2 = 13

Critical Value =2.16 = [using excel = TINV (0.05, 13)]

Marginal Error = Critical Value * standard error

= 2.16 * 0.205

= 0.4428

-0.245 \pm2.160(0.205)

8 0
2 years ago
Read 2 more answers
A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un
Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

H_{0}:p1=p2

H_{a}:p1≠p2

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }  where

  • p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
  • p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
  • p is the pool proportion of p1 and p2 (\frac{15+12}{100+100}=0.135)
  • n1 is the sample size of the students from West University (100)
  • n2 is the sample size ofthe students from East University (100)

Then we have z=\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } } ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0
2 years ago
The sum of twice x2 added to 7x is –3. Which<br> could be the value of x?
amm1812

Answer:

x= -1/3

Step-by-step explanation:

2x+7x=-3

9x/9= -3/9

x = -1/3

7 0
1 year ago
If 2A:3B=5:6 and 3B:2C=36:15 then find A:C​
Aleonysh [2.5K]

Answer:

A: C = 2: 1

Step-by-step explanation:

Please see the attached pictures for the full solution.

Further explanantion (2nd image):

The reason why the ratio of A: C is equal to the ratio if 2A: 2C is that the number of parts of A and C is equal, which is 2 parts. If I were to divide both 2A and 2C by 2 to find the ratio of A: C, I would obtain 15: 15/2. However, ratios are expressed as whole numbers and thus, we would multiply the whole ratio by 2 again and the answer would still be 30: 15. This ratio is not in the simplest form since both can be divided by 15. Thus, dividing both sides of the ratio by 15 will leave us with the final answer of

A: C= 2: 1.

☆ An alternative method is to simplify the ratio 3B: 2C at the beginning.

3B: 2C

= 36: 15

= 12: 5

Multiply the first ratio by 2 so 3B has 12 parts in both ratios:

2A: 3B

= 10: 12

Combining the 2 ratios together,

2A: 3B: 2C

= 10: 6: 5

2A: 2C

= 10: 5

= 2: 1

A: C= 2: 1

6 0
2 years ago
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