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viktelen [127]
2 years ago
9

lorenzo rides his bike at a rate of 5 yards per second. about how many miles per hour can lorenzo ride his bike

Mathematics
1 answer:
VladimirAG [237]2 years ago
5 0
Can you send the answer choices?
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Ken normally leaves work at 5:00 pm, but he is leaving 20 minutes late today. He decides to make up time by taking the toll road
NemiM [27]

Answer:

y =1/3x+20

Step-by-step explanation:

He starts 20 minutes late so we need to add 20 minutes to the time

He travels 3 times faster so he takes 1/3 of the normal time x

y =1/3x+20

4 0
1 year ago
What is the value of x? Enter your answer as a decimal to the nearest tenth in the box.
gogolik [260]

ANSWER

23.6 feet

EXPLANATION

The given triangle is a right triangle.

The hypotenuse is 27 ft.

The given angle I s 29°

The unknown side x, is adjacent to the given angle.

We use the cosine ratio to get,

\cos(29 \degree)  =  \frac{adjacent}{hypotenuse}

\cos(29 \degree)  =  \frac{x}{27}

We multiply both sides by 27 to get;

x = 27\cos(29 \degree)

x = 23.6ft

to the nearest tenth.

7 0
1 year ago
Read 2 more answers
A piece of rubber tubing maintains a cylindrical shape as it is stretched. At the instant that the inner radius of the tube is 2
professor190 [17]

Answer:

the rate of change in volume is dV/dt = 4π mm³/s = 12.56 mm³/s

Step-by-step explanation:

since the volume V of a cylinder is related with the height H and the radius R through:

V = πR²*H

then the change in time is given by the derivative with respect to time t

dV/dt = (∂V/∂R)*(dR/dt) + (∂V/∂H)*(dH/dt)

the change in volume with radius at constant height is

(∂V/∂R) = 2*πR*H

the change in volume with height at constant radius is

(∂V/∂H) = πR²

then

dV/dt = 2π*R*H *(dR/dt) + πR²*(dH/dt)

replacing values

dV/dt = 2π* 2 mm * 20 mm  * (-0.1 mm/s) + π (2 mm) ²* 3 mm/s = 4π mm³/s

dV/dt = 4π mm³/s = 12.56 mm³/s

7 0
1 year ago
Jack,sally, and joe all work in a bookstore.jack sold 126 books.joe 1/2 as many books as jack,and sally sold 1/3 as many books a
Darina [25.2K]

Sally sold 2302323 books!

7 0
2 years ago
Suppose that a person with a push mower can mow a large lawn in 5 ​hours, whereas the lawn can be mowed with a riding lawn mower
Reil [10]
------------------------------------------------------------------
Push Mower
------------------------------------------------------------------
It takes 5 hours to complete the job
1 hour = 1/5 of the job

------------------------------------------------------------------
Riding Lawn Mower
------------------------------------------------------------------
It takes 3 hours to complete the job
1 hour = 1/3 of the job

------------------------------------------------------------------
Push Mower + Riding Lawn Mower
------------------------------------------------------------------
1 hour = 1/5 + 1/3 
1 hour = 3/15 + 5/15 
1 hour = 8/15 of the job.

------------------------------------------------------------------
Calculate time needed to complete
------------------------------------------------------------------
8/15 of the job takes 1 hour
8/15 of the job = 1 hour 

------------------------------------------------------------------
Divide by 8/15 on both side
------------------------------------------------------------------
8/15 ÷ 8/15 of the job = 1 ÷ 8/15 hour
Whole of the job = 1 x 15/8 hours
Whole of the job = 15/8 hours
Whole of the job = 1 7/8 hours

------------------------------------------------------------------
Answer: 1 7/8 hours
------------------------------------------------------------------

6 0
1 year ago
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