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1 year ago

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A shop owner has 75 pounds of coffee that costs $4.50 per pound. How much coffee that costs $3.50 per pound should he mix with t

his coffee to sell the mix at the price $4.00 per pound?

2 answers:

zavuch27 [327]1 year ago

8 0

Answer:

75lbs

Step-by-step explanation:

75 out weighs the other 75 equakizing $3.5 and $4.5 to get 4. Don't worry I checked this with the RSM question I got

user100 [1]1 year ago

7 0

58 pounds of coffee

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Marty and Ethan both wrote a function, but in different ways.

marishachu [46]

<em><u>Question:</u></em>

Marty and Ethan both wrote a function, but in different ways.

Marty

y+3=1/3(x+9)

Ethan

x y

-4 9.2

-2 9.6

0 10

2 10.4

Whose function has the larger slope?

1. Marty’s with a slope of 2/3

2. Ethan’s with a slope of 2/5

3. Marty’s with a slope of 1/3

4. Ethan’s with a slope of 1/5

<em><u>Answer:</u></em>

Marty’s with a slope of 1/3 has the larger slope

<em><u>Solution:</u></em>

<em><u>Given that Marty equation is:</u></em>

$y + 3 = \frac{1}{3}(x+9)$

<em><u>The point slope form is given as:</u></em>

$y - y_1 = m(x-x_1)$

Where, "m" is the slope of line

On comapring both equations,

$m = \frac{1}{3}$

<em><u>Ethan wrote a function:</u></em>

Consider any two values from the table we have;

(0, 10) and (2, 10.4)

<em><u>The slope is given by formula:</u></em>

$m = \frac{y_2-y_1}{x_2-x_1}$

From above two points,

$(x_1, y_1) = (0, 10)\\\\(x_2, y_2) = (2, 10.4)$

Therefore,

$m = \frac{10.4-10}{2-0}\\\\m = \frac{0.4}{2} \\\\m = 0.2$

Thus we get,

$\text{Slope of Ethan} < \text{Slope of Marty}$

Therefore, Marty’s with a slope of 1/3 has the larger slope

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2 years ago

Read 2 more answers

What is √6 divided by √5 in simplest radical form?

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2 years ago

The cost of phone is reduced by 30% new cost is 116.83 what was the original price of the phone

slava [35]

Answer:

p = $116.83/0.70 = $166.90

Step-by-step explanation:

let p represent the original price. Then:

(1.00 - 0.30)p = $116.83, or

0.70p = $116.83.

Finally,

p = $116.83/0.70 = $166.90

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2 years ago

Madden and Jenn both worked at the coffee shop today. Madden's total cups of coffee made is represented by f(x); and Jenn's tota

AnnZ [28]

Answer:

The answer is D. 12x - 3.

Step-by-step explanation:

To add these functions, we just add the terms.

f(x) + g(x) = (7x - 4) + (5x + 1)

7x - 4 + 5x + 1 | Simplify

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The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally

Alex Ar [27]

Answer:

(a) The distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c) The middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of sodium consumed.

The random variable <em>X</em> has an average value of, <em>μ</em> = 9.8 grams.

The standard deviation of <em>X</em> is, <em>σ</em> = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable <em>X</em> follows a normal distribution with parameters <em>μ</em> = 9.8 grams and <em>σ</em> = 0.8 grams.

Thus, the distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of Normal distribution it is better to first convert the raw score (<em>X</em>) to <em>z</em>-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

$P(8.8$

$=P(-1.25$

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

$P(x_{1}$

Compute the value of <em>z</em> as follows:

$P(-z$

The value of <em>z</em> for P (Z < z) = 0.65 is 0.39.

Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5$ $z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1$

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

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