For this case we have a function of the form:
Where,
A: initial amount
b: decrease rate
x: time in years
Substituting values we have:
For 2010 we have:
Answer:
an exponential decay function to model this situation is:
y = 1300 * (0.97) ^ x
The population in 2010 is:
y = 1083
14,999(1+.o825)^4= 20,595. $429x48 months= 20,592
Interest rate 8 1/4%
Check 20592/14999= 1.37289
Log(1.37289)/ log(1.0825)= 3.99 years
Step-by-step explanation:
Start by writing 492,623 in standard form
4 hundred thousands + 9 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones
We can write this in other ways by moving a digit to the next smaller place value. For example, we move the 4 one place to the right to get 49 ten thousands:
49 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones
Then, we can move the 49 ten thousands to the right to get 492 thousands, and we can move 6 hundreds to the right to get 62 tens.
492 thousands + 62 tens + 3 ones
Or, we can do this:
4926 hundreds + 23 ones
Answer:
Four
Step-by-step explanation:
1. $3.10 divide by 5 = $0.62
2. $0.62 multiply by 4 = $2.48
So Levi bought 4 oranges
