Answer: The number of granola bars in one pack = 8
The number of fruit rolls in one pack = 12
Step-by-step explanation:
Let x be the number of granola bars in each pack and y be the number of fruit rolls in each pack .
Then according to the question we have the following system of equations :
Multiply equation (1) by 2 we get
Subtract equation (2) from equation (3), we get
Substitute x=8 in (1), we get
Hence, the number of granola bars in one pack = 8
The number of fruit rolls in one pack = 12
The Given Sequence is an Arithmetic Sequence with First term = -19
⇒ a = -19
Second term is -13
We know that Common difference is Difference of second term and first term.
⇒ Common Difference (d) = -13 + 19 = 6
We know that Sum of n terms is given by :
Given n = 63 and we found a = -19 and d = 6
The Sum of First 63 terms is 10521
Answer:
The bonus will be paid on at least 4099 units.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the percentile of this measure.
In this problem, we have that:
The highest 5 percent is the 95th percentile.
Past records indicate that, on the average, 4,000 units of a small assembly are produced during a week. The distribution of the weekly production is approximately normally distributed with a standard deviation of 60 units. This means that .
If the bonus is paid on the upper 5 percent of production, the bonus will be paid on how many units or more?
The least units that the bonus will be paid is X when Z has a pvalue of 0.95.
Z has a pvalue of 0.95 between 1.64 and 1.65. So we use
The number of units is discrete, this means that the bonus will be paid on at least 4099 units.