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irakobra [83]
2 years ago
8

Peter Johnson, the CFO of Homer Industries, Inc is trying to determine the Weighted Cost of Capital (WACC) based on two differen

t capital structures under consideration to fund a new project. Assume the company’s tax rate is 30%.
Component Scenario 1 Scenario 2 Cost of Capital Tax Rate
Debt $5,000,000.00 $2,000,000.00 8% 30%
Preferred Stock 1,200,000.00 2,200,000.00 10%
Common Stock 1,800,000.00 3,800,000.00 13%
Total $8,000,000.00 $8,000
Mathematics
1 answer:
Rzqust [24]2 years ago
7 0

Answer:

Scenario 1 has WACC of 7.93%

Scenario 2 has WACC of 10.33%

Step-by-step explanation:

WACC=Ke*E/V+Kp*P/V+Kd(after tax)*D/V

Ke is the cost of equity =13%

Kp is the cost of preferred stock=10%

Kd(after tax) is the cost of debt of 8% adjusted for tax as below:

Kd(after tax )=Kd(before tax)*(1-t)

t is the tax rate of 30% or 0.3

Kd(after tax)=8%*(1-0.3)=5.60%

E is equity value,which is $1.8 million under scenario 1 and $3.8 under scenario 2

P is the value of preferred stock which is $1.2 million and $2.2 million respectively

D is the value of debt which is $5 million and $2 million

V=total value of capital structure=$8 million in both cases.

Scenario 1 WACC

WACC=13%*1.8/8+10%*1.2/8+5.6%*5/8=7.93%

Scenario 2 WACC

WACC=13%*3.8/8+10%*2.2/8+5.6%*2/8=10.33%

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WILL GIVE BRAINLIEST ANSWER!!
Natasha2012 [34]
Check the picture below.

now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.

and 29' is just 29/60 degrees or about 0.48 degrees.

so 16°23' is about 16.38°, and 49°29' is about 49.48°

\bf tan(16.38^o)=\cfrac{200}{a+b}\implies a+b=\cfrac{200}{tan(16.38^o)}
\\\\\\
\boxed{b=\cfrac{200}{tan(16.38^o)}-a}
\\\\\\
tan(49.48^o)=\cfrac{200}{b}\implies \boxed{b=\cfrac{200}{tan(49.48^o)}}\\\\
-------------------------------\\\\
\cfrac{200}{tan(49.48^o)}=\cfrac{200}{tan(16.38^o)}-a\\\\\\a=\cfrac{200}{tan(16.38^o)}-\cfrac{200}{tan(49.48^o)}

make sure your calculator is in Degree mode.

4 0
2 years ago
Read 2 more answers
After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ
icang [17]

Answer:

a) Upper Control Limit = 0.10

   Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

            computer manufacturer examined samples of calls to determine

            the frequency of wrong advice given to callers. Each sample

            consisted of 100 calls.

SAMPLE             1   2   3   4   5   6   7   8   9  10 11 12 13 14 15 16

Number of errors 5  3   5   7   4   6   8   4   5    9   3   4   5   6   6   7

To find - a. Determine 95 percent limits.

              b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

  = 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

                                     = 0.0544

⇒P = 0.0544

Now,

Q = 1-P

   = 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = \sqrt{\frac{P.Q}{N} }

                             = 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

        = 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

       = 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0
2 years ago
Which system of equations below has no solution? A. y = 4x + 5 and y = 4x – 5 B. y = 4x + 5 and 2y = 8x + 10 C. y = 4x + 5 and y
Stels [109]

Answer: A  y=4x -5 and y=4x+5

Step-by-step explanation:

They have no solutions because they have the same slopes but different y intercepts. That works with any equation.

8 0
2 years ago
Question 6 (5 points)
andrew-mc [135]

Answer:

2/3

Step-by-step explanation:

if max runs 2 hours she will have 3 because 1 hour 30 times 2 is 3 hours

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2 years ago
In 2005, there were 74,250 car accidents. In 20,187 of them, the driver was a
zhuklara [117]

Answer:

27.19% probability that a female driver was involved in an accident

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

74,250 car accidents. Of those, in 20,187, the driver was a female.

Based on this, what is the probability that a female driver was involved in an accident?

p = 20187/74250 = 0.2719

27.19% probability that a female driver was involved in an accident

6 0
2 years ago
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