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Kryger [21]
2 years ago
15

dataset a has a mean of 215 and a standard deviation of 35. Dataset B has a mean of 400 and a standard deviation of 12. Which da

ta set is more spread out?
Mathematics
2 answers:
Alina [70]2 years ago
7 0

Answer:

Dataset A is more spread.

Step-by-step explanation:

The measure of spread is also known as Measure of Skewness.

For measuring the spread standard deviation is a commonly used method. As Standard deviation is the square root of the sum of square of the distance of mean value to the observation.

Thus the dataset has more standard deviation is consider as data has more spread.

Since Dataset A has more standard deviation it has more spread than dataset B.

GREYUIT [131]2 years ago
6 0
I think it is Dataset B Does that help?
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Emily wants to hang a painting in a gallery. The painting and frame must have an area of 31 square feet. The painting is 5 feet
seropon [69]
Area=legnth times width=31
the frame must go around the frame with equal legnth, x
so
the total area (meaning the frame +picture) is 5+x by 6+x
31=(5+x)(6+x)
expand
31=30+11x+x^2
minus 31 both sides
0=-1+11x+x^2
x^2+11x-1=0

answer is third one
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2 years ago
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4 0
2 years ago
If f (x) = StartFraction x minus 3 Over x EndFraction and g(x) = 5x – 4, what is the domain of (f circle g) (x)?
alexandr1967 [171]

Answer:

<h2>The domain is all real values of x except \frac{4}{5}.</h2>

Step-by-step explanation:

The function, f(x) = \frac{x - 3}{x}.

g(x) = 5x - 4.

Hence, (f circle g) (x) = \frac{5x - 4 - 3}{5x - 4}.

We need to find the domain of (f circle g) (x) .

The domain means the set of values of x, for which we will get a real value of (f circle g) (x).

The function will not give a real value when, 5x - 4 = 0 that is x = \frac{4}{5}.

Hence, the domain of the function will be all real values of x rather than \frac{4}{5}.

5 0
2 years ago
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Find a matrix representation of the transformation L(x, y) = (3x + 4y, x − 2y).
mario62 [17]

Answer:

\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

Step-by-step explanation:

The general matrix representation for this transformation would be:

\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.

\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

Solving the matrix product you have that the members of the result matrix are:

3x+4y = a*x + c*y

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So the matrix A should be:

\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]

8 0
2 years ago
The price of a train ticket consists of an initial fee plus a constant fee per stop.
murzikaleks [220]

Answer:

Initial Fee is $2.

Step-by-step explanation:

Given:

Stops  Price (dollars)

3         6.50

7         12.50

11         18.50

Also Given:

The price of a train ticket consists of an initial fee plus a constant fee per stop.

So let the Cost of initial fee be 'x'.

Also Let the Cost of Constant fee be 'y'.

Now Equation can framed as;

Price (P) = x + (y\times \textrm{Number of Stops})

Now According to table;

Number of stops = 3

Price = 6.50

So equation can be framed as;

x+3y =6.50 \ \ \ \ equation \ 1

Also According to table;

Number of stops = 7

Price = 12.50

So equation can be framed as;

x+7y =12.50 \ \ \ \ equation \ 2

Now Subtracting equation 1 from equation 2 we get;

(x+7y)-(x+3y) =12.50-6.50\\\\x+7y-x-3y=6\\\\4y =6\\\\y= \frac{6}{4}=\$1.5

Substituting the value of y in equation 1 we get;

x+3\times1.5=6.50\\\\x+4.5=6.50\\\\x =6.50-4.5 = \$2

Hence Initial Fee is $2.

8 0
2 years ago
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