This is a very long question. I'm not going to write all of it out but I will give you a starting point. Find your x by making y in the formula equal to 0.
2x + 3y = 1470
2x + 3(0) = 1470
2x = 1470
x = 735
Your furthest point on the x axis is (735,0).
Do the same for y.
2x + 3y = 1470.
2(0) + 3y = 1470
3y= 1470
y= 490
Your highest point is (0,490).
Now that both are plotted, draw a straight line connecting the two points. There's your graph.
Check
Answer:
C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
Step-by-step explanation:
The center for Simulation A and Simulation B will be roughly equal.
Overall Sample size of Simulation A = 1500 * 100 = 150000
Overall Sample size of Simulation B = 2000 * 50 = 100000
Since the sample size for Simulation A is greater, the variability of Simulation will be less.
Therefore, The answer is C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
Case 1: If we multiply f(x) = |x| by a fraction greater than zero and less than 1, the width of the resulting graph will increase. If the vertex of the original function is moved 2 units to the right, then we'd replace |x| with |x-2| Only the coefficient (3/4) satisfies the "wider graph" requirement here.
Next time you list answr possibilities, please type them in only one per line, or separate them with commons, semicolons or the like.
Y = 3bx - 7x
y = x(3b - 7)
Divide each side by 3b - 7 (assume that it is not zero).

Answer:
The volume of a sphere is given by:

So, we need to deduct this equation. We will walk through Calculus on the concept of a solid of revolution that is a solid figure that is obtained by rotating a plane curve around some straight line (the axis of revolution<span>) that lies on the same plane. We know from calculus that:
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![V=\pi \int_{a}^{b}[f(x)]^{2}dx](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint_%7Ba%7D%5E%7Bb%7D%5Bf%28x%29%5D%5E%7B2%7Ddx)
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Then, according to the concept of solid of revolution we are going to rotate a circumference shown in the figure, then:
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Isolationg y:
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So,
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![V=\pi \int_{a}^{b}[\sqrt{r^{2}-x^{2}}]^{2}dx](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint_%7Ba%7D%5E%7Bb%7D%5B%5Csqrt%7Br%5E%7B2%7D-x%5E%7B2%7D%7D%5D%5E%7B2%7Ddx)
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being -r and r the limits of this integral.
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Solving:
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![V=\pi[r^{2}x-\frac{x^{3}}{3}]\right|_{-r}^{r}](https://tex.z-dn.net/?f=V%3D%5Cpi%5Br%5E%7B2%7Dx-%5Cfrac%7Bx%5E%7B3%7D%7D%7B3%7D%5D%5Cright%7C_%7B-r%7D%5E%7Br%7D)
Finally:
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