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Alexus [3.1K]
2 years ago
8

Vineet solved a system of equations by substitution. In his work, he substituted an expression for one of the variables and solv

ed for the value of the other. This resulted in the equation 7 = 9. What can Vineet conclude?
Mathematics
2 answers:
gayaneshka [121]2 years ago
7 0
<h2>Answer:</h2>

He can conclude that the system of equations is inconsistent, i.e. it has no solution.

<h2>Step-by-step explanation:</h2>

We know that we get a no solution when we get a expression which is always false.

Here,

Vineet solved a system of equations by substitution.

In his work, he substituted an expression for one of the variables and solved for the value of the other.

This resulted in the equation 7 = 9.

which is a false identity.

since 7 can never be equal to 9.

<em>Hence, the system of equations is inconsistent , it has no solution.</em>

Eddi Din [679]2 years ago
3 0

He can conclude that the system of equations has no solution since one equation in it always results with false equivalency.

Hope this helps.

r3t40

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Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
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Answer:

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(b) The mean score of test A is 1210.

(c) The standard deviation of  test A is 80.

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(e) The value of median for test A is 1090.

(f) The value of IQR for test A is 290.

Step-by-step explanation:

The relation between two standardized tests <em>A</em> and <em>B</em> is:

50A=40B+50

The equation above approximates the relationship between scores on the two tests.

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(a)

Compute the lowest score on test A as follows:

A=40B+50\\=(40\times21)+50\\=890

Thus, the lowest score on test A is 890.

(b)

Compute the mean score of test A as follows:

<h2>A=40B+50\\=(40\times29)+50\\=1210</h2>

Thus, the mean score of test A is 1210.

(c)

Compute the mean score standard deviation of test A as follows:

<h2>A=40B+50\\=(40\times2)\\=80</h2>

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(e)

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(f)

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Answer:

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