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Evgesh-ka [11]
2 years ago
14

adam and betty purchased a printer together for $258. If adam paid $18 less than twice betty, how much money did Adam pay for th

e printer?
Mathematics
2 answers:
LenKa [72]2 years ago
4 0

Answer:

Step-by-step explanation:

Let A = Adam, B = Betty

Adam and Betty purchased a printer together for $258.

This means we can say A + B = 258.

We are also told Adam paid $18 less than twice Betty.

You can write this as:

Adam = 2 x Betty - 18

A = 2B - 18

Substitute "A" into the A + B equation and you get:

A + B = 258

2B - 18 + B = 258

3B - 18 = 258

Add 18 to both sides.

3B = 258 + 18

3B = 276

Divide both sides by 3 to find B

B = 276/3 = 92 (This means Betty paid $92).

Since the total that they paid together was $258.

This means Adam pays the Total - How much Betty paid

Adam = 258 - 92 = $166

andrezito [222]2 years ago
3 0
Does 120 sound right?
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KATRIN_1 [288]
Amount of money paid by Jeremy as rent and maintenance of shop per month = $1500
Cost of raw materials and manufacturing per month = $6000
Total cost that Jeremy has to spend per month = (1500 + 6000) dollars
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Number of individual chocolates sold = 2400
Number of chocolates sold in boxes = 50 boxes
                                                           = (12 * 50) chocolates
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Now
Price of each chocolate = 7500/3000 dollars
                                       = 75/30 dollars
                                       = 5/2 dollars
                                       = 2.5 dollars
Price of 600 chocolates = 600 * (5/2) dollars
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Price of 12 chocolates = (1500/600) * 12
                                     = 15 * 2
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Then
We can say that each box of chocolate should be sold at $30. All the loose chocolates should be sold at $2.5 each.
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w=3.12
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Answer:

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Step-by-step explanation:

Given

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Required

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