Yun was trying to factor 7x^2-14x7x

Mathematics

2 answers:

disa [49]2 years ago

8 0

the width of Yun's area model is 7x units or ( x-2 )units .

<u>Step-by-step explanation:</u>

Here we have , Yun was trying to factor 7x^2-14x. He found that the greatest common factor of these terms was 7x and made an area model: What is the width of Yun's area model. Let's find out:

We know that area of rectangle :

⇒ $Area = length(width)$ .........(1)

Now , According to question we have

⇒ $Area = 7x^2-14x$

⇒ $Area = 7x(x-2)$

Comparing this equation to equation (1) we get that :

⇒ $width = 7x$ or , $width =x -2$

Therefore , the width of Yun's area model is 7x units or ( x-2 )units .

ANEK [815]2 years ago

8 0

49x

Step-by-step explanation:

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Annie is creating a stencil for her artwork using a coordinate plane. The beginning of the left edge of the stencil falls at (2,

taurus [48]

Answer:

(A)(12, 9)

Step-by-step explanation:

Given:

The beginning of the left edge of the stencil falls at (2, −1).

A point, say Q on the stencil is at (4, 1).

Point Q divides the stencil into the ratio 1:4.

We are required to find the end of the stencil.

Mathematically, Point Q divides the stencil internally in the ratio 1:4.

For internal division of a line with beginning point $(x_1,y_1)$ and end point $(x_2,y_2)$ in the ratio m:n, we use the formula

$Q(x,y)=(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n} )$

$(x_1,y_1)=(2, -1)$ , $(x_2,y_2)=?$ , Q(x,y)=(4,1), m:n=1:4

Therefore:

$(4,1)=(\dfrac{1x_2+4*2}{1+4} ,\dfrac{1y_2+4*-1}{1+4} )\\(4,1)=(\dfrac{x_2+8}{5} ,\dfrac{y_2-4}{5} )\\$Therefore:\\\dfrac{x_2+8}{5}=4\\x_2+8=4X5\\x_2=20-8=12\\$Similarly\\\dfrac{y_2-4}{5}=1\\y_2-4=5\\y_2=4+5=9\\(x_2,y_2)=(12,9)$