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2 years ago

18.Find the value of x rounded to the nearest tenth.

Mathematics

2 answers:

dusya [7]2 years ago

5 0

Cross multiply:

6 * 8 = 9*x

48 = 9x

x = 48/9

x = 5.3

The answer is D.

Lena [83]2 years ago

4 0

Answer:

D) x = 5.3 .

Step-by-step explanation:

Given : Two triangles.

To find : .Find the value of x rounded to the nearest tenth.

Solution : We have given two similar triangle

By the property of similar ratio of sides are equal.

Then,

$\frac{6}{x} = \frac{9}{8}$ .

On cross multiplication

6 * 8 = 9 * x .

48 = 9 *x

On dividing by 9 and switching sides.

x = $\frac{48}{9}$ .

x = 5 .33

x = 5.3

Therefore, D) x = 5.3 .

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15 points!!!

r-ruslan [8.4K]

Answer:

The correct option is 4.

Step-by-step explanation:

If a figure it dilated by scale factor k, then the image and preimage are similar figures and their corresponding sides are proportional.

In triangle I, the base of the triangle is 1 unit and length of the perpendicular is 1 units.

In triangle II, the base of the triangle is 1 unit and length of the perpendicular is 2 units.

$\frac{1}{1}\neq \frac{1}{2}$

The corresponding sides are not proportional. It means both triangles are not similar. So, there is no dilation transforming triangle I into triangle II.

Therefore the correct option is 4.

6 0

2 years ago

Read 2 more answers

Rectangle ABCD with coordinates A(1,1), B(4,1), C(4,2) and D(1,2) dilates with respect to the origin to give rectangle A’B’C’D’.

Delvig [45]

Answer: Option C.

Step-by-step explanation:

You need to find the distance AB with the formula for calculate the distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Then, substituting the coordinates of the points A(1,1) and B(4,1), you get:

$AB=\sqrt{(4-1)^2+(1-1)^2}=3$

You know that A'B'=6, then the scale factor of dilation can be calculated with:

$k=\frac{A'B'}{AB}$

Substituting values, you get:

$k=\frac{6}{3}\\\\k=2$

This matches with the option C.

8 0

2 years ago

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Bones Brothers & Associates prepare individual tax returns. Over prior years, Bones Brothers have maintained careful records

madreJ [45]

Answer:

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

3 0

2 years ago

Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of

bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

= $\frac{7}{100}$

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = $1-\frac{7}{100}$

⇒ prob = $\frac{93}{100}$

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = $(\frac{93}{100})^{12}$