Answer:
(D)y ≤ 3x − 1 y ≥ −x + 4
Step-by-step explanation:
The line f(x) is solid and goes through the points (0, 4) and (4, 0) and is shaded above the line.
The line that satisfies the point (0,4) and (4,0) is y=-x+4
Since it is shaded above the line, we have the inequality sign ≥.
Therefore, one of the lines is y≥-x+4
In the equation of the line y=3x-1
When x=0, y=3(0)-1=-1
When x=2, y=3(2)-1=5
Since it is shaded below the line, we have the inequality sign ≤ .
Therefore, the other line is y≤3x-1.
The correct option is D.
Answer:
Therefore the latitude closest to the equator is 6.49°(approx).
Step-by-step explanation:
Given the path of a solar ellipse is modeled by
where f(t) is the latitude in degrees south of the equator at t minutes.
We know that ,
The minimum or maximum value of a function y(t) =at²+bt+c
is when 
In this case a= 0.00223, b= - 0.558 and c= 41.395.
The minimum value of f(t)
when 
=125.11
Therefore the latitude closest to the equator is
f(125.11)=0.00223(125.11)²-0.558×125.11+41.395
≈6.49
Answer:
The equation is;
S = 18 - 1.5t
Step-by-step explanation:
From the question, we are made to know that the depth of the snow is S and the time taken to melt in hours is t
After 4 hours of melting, the snow depth is 12 inches
Now, recall that the rate of melting is 1.5 inches/ hour
So in the 4 hours, the amount of snow melted will be 1.5 * 4 = 6 inches
So the total depth of the snow initially will be 6 + 12 = 18 inches
So let’s write the equation;
S = 18 - 1.5t
Where S is the depth of the snow after a particular number of hours t
Answer:
a. 
b. 6.1 c. 0.6842 d. 0.4166 e. 0.1194 f. 8.5349
Step-by-step explanation:
a. The distribution of X is normal with mean 6.1 kg. and standard deviation 1.9 kg. this because X is the weight of a randomly selected seedless watermelon and we know that the set of weights of seedless watermelons is normally distributed.
b. Because for the normal distribution the mean and the median are the same, we have that the median seedless watermelong weight is 6.1 kg.
c. The z-score for a seedless watermelon weighing 7.4 kg is (7.4-6.1)/1.9 = 0.6842
d. The z-score for 6.5 kg is (6.5-6.1)/1.9 = 0.2105, and the probability we are seeking is P(Z > 0.2105) = 0.4166
e. The z-score related to 6.4 kg is 
and the z-score related to 7 kg is 
, we are seeking P(0.1579 < Z < 0.4737) = P(Z < 0.4737) - P(Z < 0.1579) = 0.6821 - 0.5627 = 0.1194
f. The 90th percentile for the standard normal distribution is 1.2815, therefore, the 90th percentile for the given distribution is 6.1 + (1.2815)(1.9) = 8.5349
Answer:
C. (Chanterelle mushrooms cost less by $0.90)
Step-by-step explanation:
Divide 11.25 by 2/3, for the total amount of pound for the Cremini.
Do the same thing for Chanterelle, but the numbers given for it.
We than find out that Cremini=16.87, and Chanterelle=15.98
Now that we know Cremini is more that Chanterelle, we need to find the difference, by subtracting The bigger number by the smaller number.
Our answer is 0.89, but we will round it to 0.90.
Now we know that the Cremini costs more by $0.90, and the Chanterelle costs less by $0.90
