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1 year ago

Alana has 12.5 cups of flour with which she is baking

Mathematics

2 answers:

Vladimir [108]1 year ago

8 0

Answer:

Four times the amount of flour for the raisin bread plus 2.5 cups equals 12.5 cups total. The equation is 4x + 2.5 = 12.5. First, I subtract 2.5 from both sides, and then I divide both sides by 4. Each loaf contains 2.5 cups of flour.

This is the sample answer, I hope this helps.

almond37 [142]1 year ago

4 0

Answer:

12.5=4x+2.5 is the equation. First you would subtract 2.5 from both sides, leaving 10=4x. Then you divide by 4 and your answer would be x=2.5

Step-by-step explanation:

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A hot air balloon is floating above a straight road. To estimate their height above the ground, the balloonists simultaneously m

san4es73 [151]

Answer:

$h=1.99 miles$

Step-by-step explanation:

Let's call $h$ the balloon's height above the ground and $b$ the horizontal distance between the balloon and the first milepost.

If the angle of the depression of this milepost is 24 degrees, we can say the following:

$tan(24)=\frac{h}{b}$

$b=\frac{h}{tan(24)}$ (equation 1)

For the next milepost, the horizontal distance between the balloon and tihs milepost will be $(b+1)miles$ and the angle of depression will be 20 degrees, so we can say the following

$tan(20)=\frac{h}{b+1}$

$b+1=\frac{h}{tan(20)}$

$b=\frac{h}{tan20}-1$

then, replacing from equation 1

$\frac{h}{tan(24)} =\frac{h}{tan(20)}-1$

$1 =\frac{h}{tan(20)}-\frac{h}{tan(24)}$

$1 =h*(\frac{1}{tan(20)}-\frac{1}{tan(24)})$

$h=\frac{1}{(\frac{1}{tan(20)}-\frac{1}{tan(24)})}$

Resolving, we'll find the value of $h$

$h=1.99 miles$

So, the balloon's height above the ground is 1.99miles

4 0

2 years ago

Two ocean beaches are being affected by erosion. The table shows the width, in feet, of each beach measured at high tide where 1

TiliK225 [7]

Answer:

1. Western erodes 2 ft/yr; Dunes builds up at 5 ft/yr

2. Sometime in 2006

3. Solve simultaneous equations

Step-by-step explanation:

1. Erosion patterns

(a) Western Beach

In 15 yr, Western Beach erodes from 100 ft to 70 ft.

The rate of erosion is 30 ft/15 yr = 2 ft/yr.

(b) Dunes Beach

In 15 yr, Dunes Beach builds up from 20 ft to 95 ft.

The rate of buildup is 75 ft/15 yr = 5 ft/yr.

2. Beaches with equal width

From the table, it appears that the beaches will have the same width sometime in year 11 (2006).

3. Best approximation

The graph below also shows that it happens part way through year 11 (2006).

We could get an even better solution by calculating the equations of the two lines and solving the simultaneous equations.

5 0

2 years ago

Kendra is buying bottled water for a class trip. She has 16 bottles left over from the last trip. She buys bottles by the case t

maria [59]

Answer=6

Given the information, the following equation can be made, where x is equal to the number of cases she needs to buy.

160=16+24x
subtract 16 from both sides
144=24x
divide both sides by 24
6=x

She will have to buy 6 cases to have a total of 160 water bottles.

8 0

1 year ago

Read 2 more answers

The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

5 0

1 year ago

T varies inversely as the square root of u. t = 3 when u = 4. Find t when u = 49.

RoseWind [281]

Answer:

t = $\frac{6}{7}$