38,496 rounded to the nearest thousand is 38,000.
Answer:
Options are missing.
The options for the above question are:
TS.1: Linear in parameters.
TS.2:No perfect collinearity
TS.3: Zero conditional mean.
TS.4: Homoskedasticity.
TS.5: No serial correlation
TS.6: Normality.
Hence the correct answer is TS1 to TS 5
Step-by-step explanation:
Assumptions TS 1 to TS 5 are the minimum set of assumptions needed to for the OLS estimates to be the best linear unbiased estimators conditional on explanatory variables for all time periods.
The assumptions of Normality is not needed for the estimators to show the BLUE property
I think you meant it to be not repeating 3 times so
You do 192/3 is 60*3= 180 leaving you with 12 which is 4*3. So 64 is A
Then it’s 300/5 which is 60
455/7. So first see, if I multiply 7 by 60 is it over or under. If it’s over then B is the least and if it is less then C is the least. So 7 *60 is 420
C Being greater, b costs least per night
First transformation.
Duadrilateral ABCD has vertices with such coordinates:
- A(15,10);
- B(15,20);
- C(20,15);
- D(20,5).
Apply a rotation by 90°counterclockwise around point A to this quadrilateral, then
- A(15,10)→A'(15,10);
- B(15,20)→B'(5,10);
- C(20,15)→C'(10,15);
- D(20,5)→D'(20,15).
Second transformation.
1. A reflection across the y axis has a rule:
(x,y)→(-x,y).
Then
- A'(15,10)→A''(-15,10);
- B'(5,10)→B''(-5,10);
- C'(10,15)→C''(-10,15);
- D'(20,15)→D''(-20,15).
2. A translation 20 units down has a rule:
(x,y)→(x,y-20).
Then
- A''(-15,10)→G(-15,-10);
- B''(-5,10)→H(-5,-10);
- C''(-10,15)→I(-10,-5);
- D''(-20,15)→J(-20,-5).
Answer: first blank -B, second blank - B.
Answer:
Her centripetal acceleration during the turn at each end of the track is 
Step-by-step explanation:
Total distance covered in one round , D= 400 m
Time taken to cover one round , T = 1 min 40 s = 100 sec
Speed of runner , 
Now centripetal acceleration is given by
where 
Thus her centripetal acceleration during the turn at each end of the track is
