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1 year ago

9x-2y=11 5x-2y=15 what is the solution to the above system of equations ASAP

Mathematics

2 answers:

natali 33 [55]1 year ago

8 0

9x - 2y = 11 ... (i)

5x - 2y = 15 ... (ii)

Subtracting equation (ii) from (i) we get;

4x + 0 = -4

4x=-4 , x = -1

Replacing x = -1 in equation (i) we get;

9(-1) - 2y = 11

-9 - 2y = 11

-2y = 20

y = 20 ÷ -2 = -10

The solution to the system of equations is (-1,-10).

Mice21 [21]1 year ago

7 0

Multiply the second row by -1

9x-2y=11
-5x+2y=-15

4x=-4
X=-1

9(-1)-2y=11

-9-2y=1
Add 9 to both sides
-2y=10
Y=-5

(-1,-5)

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2 years ago

The point (1, 4) lies on a circle that is centered at (1, 1). Which statements are correct? Check all that apply.

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the circle's radius is 3 units

the point (- 2, 1 ) lies on the circle

the equation of a circle in standard form is

(x - a)² + (y - b)² = r²

where (a, b) are the coordinates of the centre and r is the radius

the radius is the distance from the centre to the point (1, 4 ) on the circle

using (1, 4) and (1,1) in the distance formula, then

r = √(1 - 1 )² + (1 - 4)² = √(0 + 9) =√9 = 3 ⇒ r² = 9

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Hence (- 2, 1 ) lies on the circle

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Thus, (0, -3) is a solution.

Option-5 : (2, -2)
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