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nataly862011 [7]
2 years ago
11

How much alfalfa does Helmut need to add to 30L of ostrich pellets to make a feed mix that is 40% alfalfa by volume?

Mathematics
1 answer:
Nutka1998 [239]2 years ago
8 0

Answer:

  a = 20 . . . . liters

Step-by-step explanation:

To solve this, multiply the equation by 30+a:

  a = 0.4(30 +a)

  a = 12 + 0.4a . . . . . eliminate parentheses

  0.6a = 12 . . . . . . . . subtract 0.4a

  a = 12/0.6 = 20 . . . divide by the coefficient of a

20 L of alfalfa must be added

_____

<em>Check</em>

  20/(30+20) = 20/50 = 40/100 = 0.4 . . . . . . answer checks OK

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On two investments totaling $6,000, Brian lost 7% on one and earned 8% on the other. If his net annual receipts were $420, how m
lianna [129]

Answer:

the amount of money invested at the rate of 7% is $400

the amount of money invested at the rate of 8%. Is $5600

Step-by-step explanation:

Let x represent the amount of money invested at the rate of 7%.

Let y represent the amount of money invested at the rate of 8%.

The total amount of money that Brian invested is $6000. This means that

x + y = 6000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time

Considering the investment at the rate at 7%,

P = x

R = 7%

T = 1

I = (x × 7 × 1)/100 = 0.07x

Considering the investment at the rate of 8%,

P = y

R = 8

T = 1

I = (y × 8 × 1)/100 = 0.08y

If his net annual receipts were $420, it means that

0.08y - 0.07x = 420 - - - - - - - - -1

Substituting x = 6000 - y into equation 1, it becomes

0.08y - 0.07(6000 - y) = 420

0.08y - 420 + 0.07y = 420

0.08y + 0.07y = 420 + 420

0.15y = 840

y = 840/0.15 = 5600

x = 6000 - y = 6000 - 5600

x = 400

8 0
1 year ago
Juana tiene en su tienda un costal con 28 libras de azucar.Hizo seis paquetes de 2,5 kg cada uno,de los cuales vendio cinco.¿Cua
Likurg_2 [28]

Answer:

Al comienzo Juana tiene 28 libras de azúcar.

Ella hace 6 paquetes de 2.5kg cada paquete.

Entonces, entre los 6 paquetes, hay:

6*2.5kg = 15kg de azúcar.

Ahora el problema es que tenemos dos unidades distintas, kilogramos y libras.

Aca podemos usar la relación:

1k = 2.2lb.

Entonces 15kg de azúcar son 15 veces 2.2 libras:

15kg = 15*2.2lb = 33lb.

Esto nos da mas de lo que hay originalmente en el costal.

Ahora si lo pensamos como:

Solo vendió 5 paquetes de 2.5kg, entonces el sobrante queda en el costal inicial:

5*2.5kg = 12.5kg

De vuelta, 1kg = 2.2lb

12.5kg = 12.5*2.2lb = 27.5lb

En este caso hay un sobrante de:

28lb - 27.5lb = 0.5lb

6 0
2 years ago
A circle with a radius of 12 inches has an arc that measures 8 pi inches. Find the measure of the central angle determined by th
ivanzaharov [21]
We know that

[length of a circle]=2*pi*r
r=12 in
[length of a circle]=2*pi*12--------------> 24pi in

if 360° (full circle)--------------------> has a length of 24pi in
X-------------------------------------------> 8pi

X=8pi*360/24pi-----------> 120°

the answer is 120°

3 0
1 year ago
In a fruit punch drink the 3 ingredients are apple juice orange juice and cranberry juice. If 1/4 of the drink is apple juice an
forsale [732]

Answer:  The required ratio in simplest form is 7 : 5 : 8.

Step-by-step explanation:  Given that in a fruit punch drink, the 3 ingredients are apple juice orange juice and cranberry juice. \frac{1}{4} of the drink is apple juice and \frac{2}{5} is orange juice.

We are to find  the ratio of cranberry juice to apple juice to orange juice in its simplest form.

Let x, y and z be the fractions of the cranberry juice, apple juice and orange juice in the fruit punch drink.

Then, according to the given information, we have

y=\dfrac{1}{4},~~z=\dfrac{2}{5}.

Now,

x+y+z=1\\\\\\\Rightarrow x+\dfrac{1}{4}+\dfrac{2}{5}=1\\\\\\\Rightarrow x=1-\dfrac{1}{4}-\dfrac{2}{5}\\\\\\\Rightarrow x=\dfrac{20-5-8}{20}\\\\\\\Rightarrow x=\dfrac{7}{20}.

Therefore, the ratio of cranberry juice to apple juice to orange juice is given by

x:y:z\\\\\\=\dfrac{7}{20}:\dfrac{1}{4}:\dfrac{2}{5}\\\\\\=\dfrac{7}{20}:\dfrac{5}{20}:\dfrac{8}{20}\\\\=7:5:8.

Thus, the required ratio in simplest form is 7 : 5 : 8.

7 0
1 year ago
A square is formed by joining the midpoints of alternate sides of a regular octagon with side length 14 in. Find the shaded area
Darya [45]

Answer:

98(1 + 2√2) in² ≈ 375 in²

Step-by-step explanation:

Assuming the shaded region is outside of the square and inside of the octagon, we can find the area by subtracting the area of the square from the area of the octagon.

The area of a regular octagon is 2 (1 + √2) s².  We can show this by finding the area of the square outside of the octagon, and subtracting the triangles in the corners:

(s + √2 s)² − 4 (½ (½√2 s)²)

(1 + √2)² s² − 4 (½ (s²/2))

(1 + 2√2 + 2) s² − s²

2 (1 +√2) s²

The diagonal of the inner square is equal to the width of the octagon, (1+√2) s.  So the side length of the square is:

½√2 (1+√2) s

½(2+√2) s

The area of the square is therefore:

(½(2+√2) s)²

¼(2+√2)² s²

¼(4+4√2+2) s²

¼(6+4√2) s²

½(3+2√2) s²

The area of the shaded region is therefore:

2 (1 +√2) s² − ½(3+2√2) s²

½ s² (4 (1 +√2) − (3+2√2))

½ s² (4 + 4√2 − 3 − 2√2)

½ s² (1 + 2√2)

The side length of the octagon is s = 14 in, so the area is:

½ (14 in)² (1 + 2√2)

= 98(1 + 2√2) in²

≈ 375 in²

3 0
2 years ago
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