<span>Let L be the number of yards on a roll of lace ribbon.
Let S be the number of yards on a roll of satin ribbon.
We can set up two equations.
equation 1: 3L + 2S = 120 yards
equation 2: 2L + 4S = 160 yards
We can multiply (equation 1) by 2 and subtract (equation 2).
equation 1: 6L + 4S = 240 yards
equation 2: 2L + 4S = 160 yards
4L = 80 yards
L = 20 yards
equation 1: 3L + 2S = 120 yards
3(20 yards) + 2S = 120 yards
2S = 60 yards
S = 30 yards
There are 20 yards on a roll of lace ribbon.
There are 30 yards on a roll of satin ribbon.</span>
Answer:
Step-by-step explanation:
Below is the rectangle in the attachment.
Current scale:
1 cm : 6 inches
If the dimensions of the rectangle is:
Length = a cm
Width = b cm
Using the scale:
Length = a × 6 inches
Width = b × 6 inches
Using the same dimensions of the rectangle is:
Length = a cm
Width = b cm
Using the scale:
Length = a × 12 inches
Width = b × 12 inches
Note that there is an enlargement of the rectangle to form the new rectangle. The length and width of new rectangle drawn will be 2 × the length and width of the rectangle seen below.
Product of two consecutive integer so this mean that x and y but y = x+1 than
x(x+1)=1332
x^2 +x -1332 =0 so bc. you get 36*37=1332 and 37x-36x=x so you can rewriting this quadratic factorized completlie
x^2 +x -1332 = 0
(x+37)(x-36)=0
x+37=0
x=-37 so the larger integer result that will be 37
Answer:
The answer would be 4050
Step-by-step explanation:
A=wl
A=45*90
A=4050