Here is a scale drawing of a window frame that uses a scale of 1 cm to 6 inches.Create another scale drawing of the window frame
that uses a scale of 1 cm to 12 inches.
1 answer:
Answer:
Step-by-step explanation:
Below is the rectangle in the attachment.
Current scale:
1 cm : 6 inches
If the dimensions of the rectangle is:
Length = a cm
Width = b cm
Using the scale:
Length = a × 6 inches
Width = b × 6 inches
Using the same dimensions of the rectangle is:
Length = a cm
Width = b cm
Using the scale:
Length = a × 12 inches
Width = b × 12 inches
Note that there is an enlargement of the rectangle to form the new rectangle. The length and width of new rectangle drawn will be 2 × the length and width of the rectangle seen below.
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Answer:
The alternative hypothesis being tested in this example is that the tire life is of more than 60,000 miles, that is:
Step-by-step explanation:
A tire manufacturer has a 60,000 mile warranty for tread life. The company wants to make sure the average tire lasts longer than 60,000 miles.
At the null hypothesis, we test if the tire life is of at most 60,000 miles, that is:
At the alternative hypothesis, we test if the tire life is of more than 60,000 miles, that is:
Answer:
x=9,-1 and
Explanation:
we have been given with the quadratic equation
we compare the given quadratic equation with general quadratic equation
general quadratic is
from given quadratic equation a=1,b= -8,c= -9
substituting these values in the formula for discriminant
Now, to find the value of x
Formula is
Now, substituting the values we will get
And rewritting the given equation by shifting 9 to right hand side of the given equation and taking minus inside the bracket so as to convert it in the form of
Answer:
< CFE = 40°
Step-by-step explanation:
To better understand the solution, see attachment for the diagram.
Given:
BC parallel to DE
Measure of Arc BD = 58°
Measure of Arc DE = 142°
First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.
The line ST divides the arc BD and arc DE into half.
That is:
Arc SC = 1/2(arc BC) =1/2(58)
Arc SC = 29°
Arc TE = 1/2(arc DE) =1/2(142)
Arc TE = 71°
Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle
29° + Arc CE + 71° = 180°
Arc CE + 100° = 180°
Arc CE = 180-100
Arc CE = 80°
Inscribed angle = 1/2(intercepted angle)
<CFE = 1/2(Arc CE )
<CFE = 1/2(80)
< CFE = 40°
