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Anton [14]
1 year ago
12

On Friday, a bowling alley made $842.72 from lane rentals and $412.38 from the concession stand. On Saturday, their lane rentals

were down by 1/8 but the concessions increased by 1/2 . What is the total amount that the bowling alley earned in lane rentals and concessions on Friday and Saturday?
Mathematics
2 answers:
gayaneshka [121]1 year ago
7 0

Answer:

2611.05

Step-by-step explanation:

snow_tiger [21]1 year ago
4 0
On Friday, the bowling alley earned $842.72 from lane rentals. On Saturday, it earned 1/8 less. So, multiply 842.72 * .125 = $105.34 less money on Saturday. So, the total on Saturday was $842.72 - $105.34 = $737.38

It earned $412.38 on Friday concession. On Saturday, it earned 1/2 more. So, multiply $412.38 * 0.5 = $206.19 more on Saturday for a total of $412.38 + $206.19 = $618.57
grand total is 842.72 + 412.38 + 737.38 + 618.57 = 2,611.05



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A new car is purchased for 15300 dollars. The value of the car depreciates at 14.25% per year. What will the value of the car be
Andrei [34K]

Answer:

\$6,082.70  

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

where  

V is the depreciated value  

P is the original value  

r is the rate of depreciation  in decimal  

x  is Number of Time Periods  

in this problem we have  

P=\$15,300\\r=14.25\%=0.1425\\x=6\ years

substitute in the formula

V=15,300(1-0.1425)^{6}  

V=15,300(0.8575)^{6}  

V=\$6,082.70  

3 0
2 years ago
The cruise boat can carry up to 45 passengers. The company wants to know the minimum number of passengers needed per cruise to c
aksik [14]
Fixed costs:
$350 + $120 + $170 = $640
Variable costs:
x * ( $6.50 + $3.64 ) = x * 10.14
Sales income ( total ):
x * $36.40
FC + FV - Income = 0
640 + 10.14 x - 36.40 x = 0
640 - 26.26 x = 0
26.26 x = 640
x = 640 : 26.26 = 24.37
Answer:
The minimum number of passengers needed per cruise, so that the cruise company can be sure it will make a profit is 25. 
3 0
2 years ago
At UF, there are always a few days between the end of classes and the beginning of final exams. These days are meant as a study
Natalija [7]

Answer:

This sample is not representative of all UF students, since those who are not local are not considered.

Step-by-step explanation:

This is a common statistics practice, when we want to study something from a population, we find a sample of this population.

However, the sample has to be representative

For example:

I want to estimate the proportion of New York state residents who are Buffalo Bills fans. So i ask, lets say, 1000 randomly selected Buffalo residents wheter they are Buffalo Bills fans, and expand this to the entire population of New York State residents. This is not representative of all New York State residents, just Buffalo residents.

In this problem, we have that:

They conduct a phone survey (with local numbers selected at random from the student directory) calling people during "dead week". Will this sample be representative of all UF students?

They only call those students with local numbers.

However, in an university, it is expected that there will be a good percentage of non local students.

So this sample is not representative of all UF students, since those who are not local are not considered.

8 0
2 years ago
A jury pool consists of 27 people. How many different ways can 11 people be chosen to serve on a jury and one additional person
hichkok12 [17]

Answer:

208,606,320

Step-by-step explanation:

A jury pool consists of 27 people. 11 people be chosen to serve on a jury and one additional person be chosen to serve as the jury foreman

Total of 27 people. 11 people can be selected from 27 people in 27C11 ways

27C11= \frac{27!}{11!(27-11)!} =13037895

one additional person be chosen to serve as the jury foreman

after selecting 11 people , remaining  is 27 - 11= 16 people

Now 1 is selected from 16 in 16 ways

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4 0
2 years ago
In a study of hormone supplementation to enable oocyte retrieval for assisted reproduction, a team of researchers administered t
olchik [2.2K]

Answer:

Note: This question is incomplete and complete question is posted down below with multiple choice questions and from Option 3 is correct

Step-by-step explanation:

Note: This question is incomplete and it is a multiple choice question. With the following multiple choices to select from.

1. The researchers expect that 80% of all similarly constructed intervals will contain the true mean number of oocytes that could be retrieved from the population of women aged 36-40 years.

2. The researchers expect that 80% of all similarly constructed intervals will contain the mean number of oocytes retrieved in the sample of 98 women aged 36-40 years.

3. There is a 80% chance that the the true mean number of oocytes that could be retrieved from the population of women aged 36-40 years is uniquely contained in the reported interval.

4. The researchers expect that 80% of all similarly constructed intervals will contain the range of the number of oocytes that could be retrieved from the population of women aged 36-40 years.

we have to select the appropriate answer from the above options.  

So, in order to choose the correct option, first we need to understand the confidence interval.

Confidence Interval is a range of value for which are pretty sure our true values will lie in that interval. For example, in this question, we have 80% confidence interval and it means there is a 80% confident chance that our true values will lie in that 80% interval. Let's calculate it.

We have following data given from the question.    

Sample = 98

Mean = 9.7

Confidence Interval = 80%

Z = 1.282

And formula for confidence interval is :

Mean ± Z x SD/\sqrt{n}

For this equation, we have all quantities except SD which is standard deviation. Let's calculate it first.

Standard deviation is square root of variance and so we need to calculate variance first.

Mean = Sum/ total number

9.7 = Sum/ 98

Sum = 950.6

For variance we will use this sum.

s² = (950.6 (1 - 9.7)²) ÷ (98-1)

s² = 741. 762 = Variance.

Let's calculate Standard deviation

SD = \sqrt{variance}

SD = \sqrt{741.762}

SD = 27.23 = Standard Deviation.

Now, we have complete data to calculate range of values for the confidence interval of 80%

Mean ± Z x SD/\sqrt{n}

Here, Z is the Z-score and it has predetermined value for different confidence intervals and here in our case for 80% , Value of Z = 1.282

Now, by just plugging in the values in to above formula we will get range of values or confidence interval of 80% in which our true value will likely to lie.

9.7 ± 1.282 x 27.23/\sqrt{98}

9.7 ± 3.52 Or

9.7 + 3.52 = 13.22

9.7 - 3.52 = 6.18

Rangle of Values with confidence interval of 80% = (6.18 to 13.22).

Which means that, our true mean will most likely lie in this interval.

So, the option 3 is correct which meets the correct definition and interpretation of the problem.  

6 0
2 years ago
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