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1 year ago

Solve the equation -10 (g - 6) = -65

Mathematics

1 answer:

Elanso [62]1 year ago

5 0

Step-by-step explanation:

$- 10(g - 6) = - 65 \\ - 10g + 60 = - 65 \\ - 10g = - 125 \\ 10g = 125 \\ g = \frac{25}{2}$

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Point F is on circle C. What is the length of line segment GF? 12.5 units 15.0 units 17.5 units 20.0 units

geniusboy [140]

The answer:
According to the image, the length of line segment GF can be found with
GF= GC +CF
CF is one the radius, so CF=7.5
to find GC, we can apply Pythagorean theorem on the right triangle GEC
it is
GC² =GE² + EC² = 10² +7.5² =156.25, and then GC= sqrt(156.25)=12.5

therefore, GF= GC +CF=12.5+7.5=20

so the answer is 20.0 units

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1 year ago

Find the error sienna used base-ten blocks to find 45÷3 .explain her error

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2 years ago

A farmer is estimating the surface area of his barn to find how much paint he needs to buy. One part of the barn is triangular a

Nady [450]

We know the triangle is an isosceles triangle. So, we use the Pythagorean Theorem.

a^2+b^2=c^2

The c would be 22, because it's the longest edge. Now find a or b. They are the same, that is how you find the two sides of the triangle for part A.

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Plug in the numbers for that formula and the answer would be found for part B.

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2 years ago

According to Net Market Share, Microsoft's Internet Explorer browser has 53.4% of the global market. A random sample of 70 users

Natalija [7]

Answer:

Probability that 32 or more from this sample used Internet Explorer as their browser is 0.9015.

Step-by-step explanation:

We are given that according to Net Market Share, Microsoft's Internet Explorer browser has 53.4% of the global market.

A random sample of 70 users was selected.

Let $\hat p$ = sample proportion of users who used Internet Explorer as their browser.

The z score probability distribution for sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, p = population proportion of users who use internet explorer = 53.4%

$\hat p$ = sample proportion = $\frac{32}{70}$ = 0.457

n = sample of users = 70

Now, probability that 32 or more from this sample used Internet Explorer as their browser is given by = P( $\hat p$ $\geq$ 0.457)

P( $\hat p$ $\geq$ 0.457) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\geq$ $\frac{0.457-0.534}{\sqrt{\frac{0.457(1-0.457)}{70} } }$ ) = P(Z $\geq$ -1.29)

= P(Z $\leq$ 1.29) = 0.9015

The above probability is calculated by looking at the value of x = 1.29 in the z table which has an area of 0.9015.

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azamat

There is only 1 real number solution

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2 years ago