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Tamiku [17]
1 year ago
15

There are 3 identical wooden blocks that are 50 inches long, 5 inches wide and 3 inches thick. If you glue them together, what i

s the largest and smallest surface area you can get?? PLZZ I will give you 100 pointd
Mathematics
2 answers:
nika2105 [10]1 year ago
5 0

welp

ok so first what you do is you find out which sides have the smallest and largest surface areas

largest: 50x5 (250in)

smallest: 5x3 (15in)

what you would do if you wanted the smallest surface is you would glue the 50x5 surfaces together like this: |_| if the 5in sides are facing to the side

smallest like this: ||| if the 5in sides are facing to the side

CALCULATE:

50*5+53*5+53*5+3*5+3*5+50*5+50*5+47*5+2*5*10*3*3

simplifies to:

489*5

2445

LARGEST SURFACE AREA

CALCULATE:

9*5+9*5+50*5+50*5+9*5*10+9*5*10

simplifies to:

289*5

1445

SMALLEST SURFACE AREA

finlep [7]1 year ago
4 0

Answer:

336 inches of surface area

Step-by-step explanation:

The explanation is the picture.  I hope this answers your question.

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The segments shown below could form a triangle.
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A. True

Step-by-step explanation:

The Triangle Inequality Theorem says that the sum of any two sides must be greater than the third side. Let's see if this is true.

a + b

9 + 1 = 10>9

a + c

9 + 9 = 18>1

c + b

9 + 1 = 10>9

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A rare first-edition book is currently priced at $200. After one year, the price of the book is anticipated to be 1.15 times the
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How to solve the equation
motikmotik
Answer: c

given volume is 125 cc

cube root of 125 is 5

aka 5×5×5=125

and 6×5×5=150

hence answer is c
5 0
1 year ago
Barbara drives between Miami, Florida, and West Palm Beach, Florida. She drives 50 mi in clear weather and then encounters a thu
NeX [460]

Distance traveled in clear weather = 50 miles

Distance traveled in thunderstorm = 15 miles

Let speed in clear weather = x

⇒ Speed in thunderstorm = x-20

Total time taken for trip = 1.5 hours

We need to determine average speed in clear weather (i.e. x) and average speed in the thunderstorm (i.e. x-20 ).

Total time taken for trip = Time taken in clear weather + Time taken in thunderstorm

⇒ Total time taken for trip = \frac{Distance covered in clear weather}{Speed in clear weather} + \frac{Distance covered in thunderstorm}{Speed in thunderstorm}

⇒ 1.5 = \frac{50}{x} + \frac{15}{x-20}

⇒ 1.5 = \frac{50(x-20)+15(x)}{(x)(x-20)}

⇒ 15*x*(x-20) = 10*[50*(x-20)+15*x]

⇒ 15x² - 300x = 500x - 10,000 + 150x

⇒ 15x² - 300x = 650x - 10,000

⇒ 15x² - 950x + 10,000 = 0

⇒ 3x² - 190x + 2,000 = 0

The above equation is in the format of ax² + bx + c = 0

To determine the roots of the equation, we will first determine 'D'

D = b² - 4ac

⇒ D = (-190)² - 4*3*2,000

⇒ D = 36,100 - 24,000

⇒ D = 12,100

Now using the D to determine the two roots of the equation

Roots are: x₁ = \frac{-b+\sqrt{D}}{2a} ; x₂ = \frac{-b-\sqrt{D}}{2a}

⇒ x₁ = \frac{-(-190)+\sqrt{12,100}}{2*3} and x₂ = \frac{-(-190)-\sqrt{12,100}}{2*3}

⇒ x₁ = \frac{190+110}{6} and x₂ = \frac{190-110}{6}

⇒ x₁ = \frac{300}{6} and x₂ = \frac{80}{6}

⇒ x₁ = 50 and x₂ = 13.33

So speed in clear weather can be 50 mph or 13.33 mph. However, we know that in thunderstorm was 20 mph less than speed in clear weather.

If speed in clear weather is 13.33 mph then speed in thunderstorm would be negative, which is not possible since speed can't be negative.

Hence, the speed in clear weather would be 50 mph, and in thunderstorm would be 20 mph less, i.e. 30 mph.

7 0
2 years ago
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