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kumpel [21]
2 years ago
9

Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea

rs. Hernando plans on taking a random sample of n nn members from this population to make a 95 % 95%95, percent confidence interval for the mean age in the league. He wants the margin of error to be no more than 5 55 years. Which of these is the smallest approximate sample size required to obtain the desired margin of error?
Mathematics
1 answer:
asambeis [7]2 years ago
3 0

Answer:

n\geq 23

Step-by-step explanation:

-For a known standard deviation, the sample size for a desired margin of error is calculated using the formula:

n\geq (\frac{z\sigma}{ME})^2

Where:

  • \sigma is the standard deviation
  • ME is the desired margin of error.

We substitute our given values to calculate the sample size:

n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23

Hence, the smallest desired sample size is 23

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Amy has a box containing 6 white, 4 red, and 8 black marbles. She picks a marble randomly. It is red. The second time, she picks
kati45 [8]

Answer: The probability that the fourth marble Amy picks is black =\frac{8}{15}

The probability that in the fifth attempt she will pick a red or a black marble P(R∩B) =\frac{5}{7}


Step-by-step explanation:

To find  the probability that in the fifth attempt she will pick a red or a black marble P(R∩B) .

The total marble in beginning=6+4+8=18

After 3 attempts, the total  marbles left=18-3=15

The number of black marbles =8

The probability that the fourth marble Amy picks is black =\frac{8}{15}

As four marble has already picked up, then the total marbles left in the box

=18-4=14

Now, as a red marble is already picked in 1st attempt , the number of red marbles in the box now= 4-1=3

And a black marble is already picked in fourth attempt , the number of black marbles in the box now= 8-1=7

Now P(R∩B)=P(R)+P(B)=\frac{3}{14}+\frac{7}{14}=\frac{10}{14}=\frac{5}{7}

7 0
2 years ago
Will you consider these mathematical phrases as polynomials?​
ELEN [110]

What phrases? I don't see a photo or any other information. •_•

4 0
1 year ago
Christmas Tree lights are used not only for Christmas trees, but sometimes to decorate college dorm rooms. Suppose that a string
puteri [66]

Answer: Hello!

Ok, because the bulbs are wired in series, then if only one fails, all the string fails.

Then we need to see the probability for the 20 bulbs to not fail.

If the probability for each bulb to fail is 0.02, then the complement (or the probability of working fine) is 1 - 0.02 = 0.98

then we have 20 bulbs, and each one has a probability of 0.98 of working alright, then the probability for all them to work alright is the multiplication of this probabilities, this is

0.98^{20} = 0.6676

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then the correct answer is c.

6 0
1 year ago
Without using a calculator, what is 30% of 546? (You can round up to avoid decimal points)
madreJ [45]

Answer:

Hey there!

We can solve this by multiplying 0.3 by 546, which is about 164.

Hope this helps :)

5 0
2 years ago
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3/4 root 10
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6 0
1 year ago
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