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tiny-mole [99]
1 year ago
7

The graphs of the function f (given in blue) and g (given in red) are plotted above. Suppose that u(x)=f(x)g(x) and v(x)=f(x)/g(

x). Find each of the following:
Mathematics
1 answer:
prisoha [69]1 year ago
8 0
I included the graphs of the functions f(x) (given in blue) and g(x) (given in red) in the attached pdf file.

The questions are:

1) Find u(1) and
2) Find v(1)

Solutions:

1) u(x) = f(x) g(x) => u(1) = f(1) * g(1)

From the graphs f(1) = 1 and g(1) = 2, then f(1)*g(1) = 1*2 =2

Answer: 2

2)  v(x) = f(x) / g(x) => v(1) = f(1) / g(1) = 1 / 2 = 0.5

Answer: 0.5
Download pdf
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Identify the rule of inference that is used to derive the conclusion "You do not eat tofu" from the statements "For all x, if x
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Answer:

1(b) ∀ (A(x) ⇒ B(x) )

2(b) ∀ (B(x) ⇒ C(x) )

3(b) ∀ (B(x) ⇒ E(x) )

Step-by-step explanation:

1) Tofu is healthy

2) Tofu is healthy to eat

3) Tofu eats what taste good

1a) For all x, if x is healthy to eat

2a) For all x, if x is not healthy to eat, then x does not taste good.

3a) For all x, if x is healthy to eat, then x is healthy to eat what tastes good

For all x in order to symbolize the statement

1(a)   2(a)  3(a)

If we use:

A(x): Tofu is healthy

B(x): Tofu is healthy to eat

C(x): Tofu eats what taste good

E(x): Tofu only eat what tastes good

If we symbolize "For all x" by the symbol ∀ then then the propositions 1(a), 2(a) and 3(a) can be written as:

1(b) ∀ (A(x) ⇒ B(x) )

2(b) ∀ (B(x) ⇒ C(x) )

3(b) ∀ (B(x) ⇒ E(x) )

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2 years ago
Two groups of students were asked how many pets they had. The table below shows the numbers for each group:
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where are the answers?
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2 years ago
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Find an equation of the line containing the centers of the two circles whose equations are given below.
Anna35 [415]

Answer:

<h2><em>3y+x = -5</em></h2>

Step-by-step explanation:

The general equation of a circle is expressed as x²+y²+2gx+2fy+c = 0 with centre at C (-g, -f).

Given the equation of the circles x²+y²−2x+4y+1  =0  and x²+y²+4x+2y+4  =0, to  get the centre of both circles,<em> we will compare both equations with the general form of the equation above as shown;</em>

For the circle with equation x²+y²−2x+4y+1  =0:

2gx = -2x

2g = -2

Divide both sides by 2:

2g/2 = -2/2

g = -1

Also, 2fy = 4y

2f = 4

f = 2

The centre of the circle is (-(-1), -2) = (1, -2)

For the circle with equation x²+y²+4x+2y+4  =0:

2gx = 4x

2g = 4

Divide both sides by 2:

2g/2 = 4/2

g = 2

Also, 2fy = 2y

2f = 2

f = 1

The centre of the circle is (-2, -1)

Next is to find the equation of a line containing the two centres (1, -2) and (-2.-1).

The standard equation of a line is expressed as y = mx+c where;

m is the slope

c is the intercept

Slope m = Δy/Δx = y₂-y₁/x₂-x₁

from both centres, x₁= 1, y₁= -2, x₂ = -2 and y₂ = -1

m = -1-(-2)/-2-1

m = -1+2/-3

m = -1/3

The slope of the line is -1/3

To get the intercept c, we will substitute any of the points and the slope into the equation of the line above.

Substituting the point (-2, -1) and slope of -1/3 into the equation y = mx+c

-1 = -1/3(-2)+c

-1 = 2/3+c

c = -1-2/3

c = -5/3

Finally, we will substitute m = -1/3 and c = 05/3 into the equation y = mx+c.

y = -1/3 x + (-5/3)

y = -x/3-5/3

Multiply through by 3

3y = -x-5

3y+x = -5

<em>Hence the equation of the line containing the centers of the two circles is 3y+x = -5</em>

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1 year ago
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Find the product. (2n + 2)(2n – 2)
vekshin1
<span>(2n + 2)(2n – 2)
= (2n)^2 -2^2
= 4n^2 - 4

hope it helps</span>
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2 years ago
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