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torisob [31]
2 years ago
13

A lock has 5 buttons. The lock is opened by pushing two buttons simultaneously and then by pushing one button alone. How many co

mbinations are possible?
Mathematics
1 answer:
Pavel [41]2 years ago
7 0

We first must calculate how many ways 2 oblects can be chosen from 5.

combinations = 5! / 2! * (5-2)!

combinations = 5*4 / 2

combinations = 10


There are 10 ways to choose the 2 buttons and 5 ways to choose the final butto so there are 10 * 5 = 50 different ways.


Source

1728.com/combinat.htm




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The following histogram represents the distribution of acceptance rates (percent accepted) among 25 business schools in 2004. In
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Answer:

  • <u><em>Option b. just below 30%</em></u>

<u><em></em></u>

Explanation:

Please, see attached the <em>histogram that represents the distribution of acceptance rates (percent accepted) among 25 business schools in 2004. </em>

<em />

The<em> median</em> is the value that separates the lower 50% from the upper 50% of the data.

Since there are 25 business schools, the middle value is the number 13.

The height of each bar is the<em> frequency</em> or number of business school for that acceptace rate:

  • The first bar has frequency of 1 school
  • The second bar has frequency of 3 schools: cummulative frequency: 1+3=4.
  • The third bar has frequency 5 schools: cummulative frequency 4 + 5 = 9.
  • The fourth bar has frequency 3 schools: cummulative frequency: 9+3=12.

Then, the 13th value is on the next bar, the fifth bar.

The fifth bar has acceptance rates 25  ≤ rate < 30.

That means that the median acceptance rate is greater than or equal to 25 and less than 30.

Thus, the choice is the option <em>b. just below 30%.</em>

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2 years ago
A piece of wire 24 ft long is cut into two pieces. One piece is used to form a square, and the remaining piece is used to form a
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Answer:

SAY WHAT

Step-by-step explanation:

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The random variable X is exponentially distributed, where X represents the waiting time to see a shooting star during a meteor s
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Answer:

The parameters of the exponential distribution is 0.0133.

Step-by-step explanation:

Exponential distribution is a continuous probability distribution.

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Here the parameter θ is the reciprocal of the mean of the random variable <em>X</em>.

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1 year ago
There are 30 businesses with 4 executives each for the new office building. Each business needs one office for each of its
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Answer:

B

Step-by-step explanation:

B is the right one because the question says that every 4 executives can go into 1 office

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2 years ago
19. Bella is putting down patches of sod
Fofino [41]

Answer:

The dimensions of the two different rectangular regions are;

1st Arrangement:

W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards

2nd Arrangement:

W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards

The perimeter of the two different rectangular regions are;

1st Arrangement:

P₁ = 18 yards

2nd Arrangement:

P₂ = 24 yards

Step-by-step explanation:

Bella is putting down patches of sod to start a new lawn.

She has 20 square yards of sod.

We are asked to provide the dimensions of two different rectangular regions that she can cover with the sod.

Recall that a rectangle has an area given by

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Where W is the width of the rectangle and and L is the length of the rectangle.

Since Bella has 20 square yards of sod,

20 = W*L

There are more than two such possible rectangular arrangements.

Out of them, two different possible arrangements are;

1st Arrangement:

20 = (4)*(5) = (5)*(4)

Width is 4 yards and length is 5 yards or width is 5 yards and length is 4 yards

2nd Arrangement:

20 = (2)*(10) = (10)*(2)

Width is 2 yards and length is 10 yards or width is 10 yards and length is 2 yards

Therefore, the dimensions of two  different rectangular regions are;

1st Arrangement:

W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards

2nd Arrangement:

W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards

What is the perimeter of each region?

The perimeter of a rectangular shape is given by

P = 2(W + L)

Where W is the width of the rectangle and and L is the length of the rectangle.

The perimeter of the 1st arrangement is

P₁ = 2(4 + 5)

P₁ = 2(9)

P₁ = 18 yards

The perimeter of the 2nd arrangement is

P₂ = 2(2 + 10)

P₂ = 2(12)

P₂ = 24 yards

So the perimeter of the 1st arrangement is 18 yards and the perimeter of the 2nd arrangement is 24 yards.

Note:

Another possible arrangement is,

20 = (1)*(20) = (20)*(1)

Width is 1 yard and length is 20 yards or width is 20 yards and length is 1 yard.

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