When tow solids of similar shape that is assuming to be a box in this case, having a length ratio of 2:9, we get the ratio of the surface areas equal to the<span>square of the ratio of their edges. This is becaue the surface area is equal to the area of the base (square) which is the square of the side. Answer is B.</span>
<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
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{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
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1. To the right of
2. To the left of
3. Below
4. (4.5, 200)
Log(x/7300000000) = 5.6 so
<span>x/7300000000 = 10^5.8 = 398107.17 </span>
<span>x = 2.9061823 x 10^15 </span>
I think it is 123 meters Answer:
Step-by-step explanation: