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1 year ago

Find cot 0 if cos 0=3/13

2 answers:

6 0

3/4 root 10
you make a right triangle. use Pythagorean theorem. and find the opposite side. then reduce the radical of 160. and do tan and then flip them around to make cot.

nekit [7.7K]1 year ago

6 0

<h2>Answer:</h2>

The value of:

$\cot \theta=\dfrac{3}{4\sqrt{10}}$

<h2>Step-by-step explanation:</h2>

We are given,

$\cos \theta=\dfrac{3}{13}$

We know that cos θ is the ratio of base and hypotenuse of a right angled triangle corresponding to θ.

On applying Pythagorean Theorem in ΔABC we get:

$13^2=3^2+a^2\\\\\\i.e.\\\\\\169=9+a^2\\\\\\a^2=160\\\\\\i.e.\\\\\\a=4\sqrt{10}$

Hence, the value of $\cot \theta$ is defined as the ratio of base to perpendicular length of the triangle.

Hence,

$\cot \theta=\dfrac{3}{4\sqrt{10}}$

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Anthony, Brian and Chris are hired for a job. If Anthony and Brian are working together they will finish the job in minutes. If

Tcecarenko [31]

Answer:

12.5

Step-by-step explanation:

Let individual time taken by Anthony, Brian and Chris = t1 , t2 , t3 respectively

So, total time taken by A & B = 1 / t1 + 1 / t2 , lets suppose = 10 {i}

Total time taken by A & C = 1 / t1 + 1 / t3 , lets suppose = 15 {ii}

Total time taken by B & C = 1 / t2 + 1 / t3 , lets suppose = 20 {iii}

From {i} , 1 / t2 = 10 - 1 / t1

From {ii} 1 / t1 = 15 - 1 / t3

By above two eqtns , 1 / t2 = 10 - (15 - 1 / t3)

1 / t2 = 1 / t3 - 5

Putting in {iii} , 1 / t3 - 5 + 1 / t3 = 20

2 / t3 = 25

t3 = 12.5

5 0

2 years ago

The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo

Lerok [7]

Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

$IQR=Q_3-Q_1=16-6.5=9.5$

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

$IQR=Q_3-Q_1=15.5-8=7.5$

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

4 0

2 years ago

After a storm damage is the community center she gotten her friend told fundraising events out pay for repairs after the first e

brilliants [131]

Question:

After a storm damages the community center, Shanika and her friends hold fundraising events to help pay for repairs. After the first event, they raise $240, which is 10% of the total amount that they want to raise. What is the total amount of money that Shanika and her friends want to raise?

Answer:

The total amount of money that Shanika and her friends want to raise is $2400

Step-by-step explanation:

Here we have the amount raised = $240

Also we are told that the amount raised is only 10% of the amount they want to raise

Therefore if we put the amount they want to raise as D we have

10% of D = $240

That is;

$\frac{10}{100} \times D = \$240$