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mr Goodwill [35]
2 years ago
11

Alan rewrites a fraction less than 1 as a decimal. The numerator is a whole number greater than 0. For which denominator will th

e fraction always convert to a terminating decimal?
Mathematics
2 answers:
klemol [59]2 years ago
6 0
The answer is D) 16

The reason why is because 16 = 2*2*2*2 has only 2 as its prime factor. Any time 2 or 5 are the prime factors of the denominator, then the decimal will terminate. Examples include fractions like 1/2, 1/5, 1/10
sp2606 [1]2 years ago
3 0

Answer:

16

Step-by-step explanation:

Took the benchmark (iready)

You might be interested in
Geometry: Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.
Kazeer [188]

It is given in the question that,

Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.

And

m \angle PQS = 2x+1
\\
m \angle RQS = 4x-15

Since QS bisects angle PQR, therefore

m \angle PQS = m \angle RQS

Substituting the values, we will get

2x+1=4x-15
\\
1+15 = 4x-2x
\\
2x = 16
\\
x = 8

6 0
2 years ago
Read 2 more answers
What is the completely factored form of f(x)=x3+5x2+4x−6?
Gre4nikov [31]
f(x)=x^3+5x^2+4x-6
f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)

Synthetic division yields

-3  |  1   5   4   -6
.    |      -3  -6    6
- - - - - - - - - - - - -
.    |  1   2  -2    0

which translates to

\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2

with remainder 0. Now by the quadratic formula,

x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3

and so

f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))
3 0
2 years ago
Noah fills a soap dispenser from a big bottle that contains 2 13 liters of liquid soap. That amount of soap will fill 3 12 dispe
Harrizon [31]

Answer:

0.68L per dispenser

Step-by-step explanation:

Big bottle contain 213L of soap.

Big bottle will fill 312 dispensers.

This means 1 each dispenser can take 213/312 litres = 0.68L per dispenser.

3 0
2 years ago
Read 2 more answers
Stacey has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches off of the width. The area of
ratelena [41]

Answer:

The side length of the original square was 6 inches

Step-by-step explanation:

we know that

The area of a square is

A=b^2

where

b is the length side of the square

Let

x ---> the length of the original square

The area of the original square is

A=x^{2}\ in^2

The length of the smaller square is

b=(x-3)\ in

The area of the smaller square is

A=(x-3)^2\ in^2

The area of the smaller square is 1/4 the area of the original square

so

(x-3)^2=\frac{1}{4} x^{2}

solve for x

x^2-6x+9=\frac{1}{4} x^{2}

Multiply by 4 both sides

4x^2-24x+36=x^{2}

4x^2-x^2-24x+36=0\\3x^2-24x+36=0

Solve the quadratic equation by graphing

using a graphing tool

x=2, x=6

see the attached figure

The solution is x=6 in

Remember that the solution must be greater than 3 inches (because Stacey cuts  3 inches off of the length of the square and 3 inches off of the width)

therefore

The side length of the original square was 6 inches

3 0
2 years ago
The engineers designing the All Aboard Railroad between Boca Raton and Jupiter decide to create parallel tracks through this por
olga2289 [7]

Answer:

there are no signs between the x and y and constant

it could be

2x+5y=15

2x+5y=-15

-2x+5y=15

2x-5y=15

for ax+by=c, the equation of a line paralell to that is

ax+by=d where a=a, b=b, and c and d are constants

(for this answer, I'm going to use 2x+5y=15)

given 2x+5y=15, the equation of a line paralell to that is 2x+5y=d

to find d, subsitute the point (4,-2), basically put 4 in for x and -2 for y to get the constant

2x+5y=d

2(4)+5(-2)=d

8-10=d

-2=d

the eqaution is 2x+5y=-2 (Only if the original equation is 2x+5y=-15

pls mark me brainlest

5 0
2 years ago
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