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katen-ka-za [31]
2 years ago
6

Estimate the value 9.9 squared times 1.79 and the square root of 97.5 divided by 1.96

Mathematics
1 answer:
Inessa05 [86]2 years ago
8 0

Answer:

200 and 5

Step-by-step explanation:

1. 9.9 rounded is 10

1.79 rounded is 2

10^2 is 100

100 x 2 = 200

2. 97.5 rounded is 100

1.96 rounded is 2

square root of 100 is 10

10/2 = 5

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Answer:

The domain of the function is the interval [0,2.23]

see the explanation

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> the height of the laptop in units

we have

h(t)=-16t^{2}+28t+17

we know that

When the laptop hits the ground, the value of h(t) is equal to zero

so

For h(t)=0

-16t^{2}+28t+17=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+28t+17=0

so

a=-16\\b=28\\c=17

substitute in the formula

x=\frac{-28(+/-)\sqrt{28^{2}-4(-16)(17)}} {2(-16)}

x=\frac{-28(+/-)\sqrt{1,872}} {-32}

x=\frac{-28(+/-)12\sqrt{13}} {-32}

x_1=\frac{-28(+)12\sqrt{13}} {-32}=-0.477

x_1=\frac{28(-)12\sqrt{13}} {32}=-0.477  ---> is not a solution

x_2=\frac{-28(-)12\sqrt{13}} {-32}

x_2=\frac{28(+)12\sqrt{13}} {32}=2.23\ sec

therefore

The domain of the function is the interval [0,2.23]

All real numbers greater than or equal to 0 seconds and less than or equal to 2.23 seconds

0\ sec \leq x \leq 2.23\ sec

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2 years ago
Jane is one of 50 students to take a standardized math test that includes 100 multiple choice questions. If she has the highest
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Answer: 87%
Solution:
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What is the completely factored form of 12xy-9x-8y+6
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Answer: (4y - 3)(3x - 2)

Step-by-step explanation: Factor the polynomial.

Hope this helps! :) ~Zane

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2 years ago
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A rocket leaves the surface of Earth at time t=0 and travels straight up from the surface. The height, in feet, of the rocket ab
erastovalidia [21]

Answer:

Remember that:

Speed = distance/time.

Then we can calculate the average speed in any segment,

Let's make a model where the average speed at t = t0 can be calculated as:

AS(t0) = (y(b) - y(a))/(b - a)

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And this has a lot of sense, because while the distance between the values of time is constant (is always 100 seconds) we can see that the difference between consecutive values of y(t) is increasing.

Then we can conclude that the rocket is accelerating upwards, then as larger is the value of t, bigger will be the average velocity at that point.

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Your answer will be A; 18%
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