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alex41 [277]
2 years ago
8

A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th

e one-way fare, 100 passengers will find other means of transportation. Let x represent the number of $1.00 increases in ticket price.
Choose the inequality to represent the values of x that would allow the carpool service to have revenue of at least $12,000. Then, use the inequality to select all the correct statements.

-100x^2 + 1,500x + 10,000 >/= 12,000
100x^2 - 1,500x - 10,000 >/= 12,000
The price of a one-way ticket that will maximize revenue is $12.50.
The price of a one-way ticket that will maximize revenue is $7.50.
The maximum profit the company can make is $4,125.00.
100x^2 + 1,500x - 10,000 = 12,000
The maximum profit the company can make is $15,625.00.
Mathematics
1 answer:
DanielleElmas [232]2 years ago
6 0

Answer:

(2000 - 100x)(5 + x)》12000

10000 - 500x + 2000x - 100x²》12000

-100x² + 1500x + 10000》12000

x for max profit:

-200x + 1500 = 0

x = 7.5

Price = 5 + 7.5 = 12.5

Max profit:

(2000 - 100(7.5))(5 + 7.5)

= 1250 × 12.5

= $15625

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A researcher wants to determine if preschool attendance is associated with high school graduation for low-income students. She r
Alik [6]

Answer:

(C) Whether or not a subject attends preschool

Step-by-step explanation:

In research studies, variables are used to explain differences in another variable. The explanatory variable (also known as independent or predictor variable) is used to explain differences in the response variable (dependent or outcome variable).

<em>It is important to know that the explanatory variable is the variable that is manipulated by the researcher. </em>

The facts that are not being manipulated are the income of the children studied, and what happens after attending or not preschool program. The variable the researcher is manipulating is the assignation to groups that will or will not attend preschool. Therefore the correct answer is:

(C) Whether or not a subject attends preschool

I hope you find this information useful and interesting! Good luck!

3 0
1 year ago
Of the 125 people in the community choir, 22 of them actually come from other communities. What fraction of the choir comes from
makvit [3.9K]
The answer is 17.6%
125/100=1.25*17.6=22
hope this helps!
3 0
2 years ago
The crew of apollo 17 consisted of 2 pilots and a geologist. Suppose that nasa had actually trained 9 pilots and 4 geologists as
Troyanec [42]

They could have assembled total 336 different possible crews.

<em><u>Explanation</u></em>

Total number of trained pilots is 9 and geologists is 4.

The crew should be consisted of 2 pilots and 1 geologist. That means, <u>2 pilots are chosen from total 9 and 1 geologist is chosen from total 4</u>.

Number of ways for choosing 2 pilots from 9 = ^9C_{3} =84 and

Number of ways for choosing 1 geologist from 4 =^4C_{1}= 4

So, the total possible number of different crews they could have assembled =84*4= 336

8 0
2 years ago
−3 1/3 ÷ 9 pllllllllllllllllllllllllllllllllllllllllllllllllll
tia_tia [17]

-\frac{10}{27}  hope this helps :)

8 0
2 years ago
A store sells 8 colors of balloons with at least 28 of each color. How many different combinations of 28 balloons can be chosen?
Len [333]

Answer:

(a) Selection = 6724520

(b) At\ most\ 12 = 6553976

(c) At\ most\ 8 = 6066720

(d) At\ most\ 12\ red\ and\ at\ most\ 8\ blue =  5896638

Step-by-step explanation:

Given

Colors = 8

Balloons = 28 --- at least

Solving (a): 28 combinations

From the question, we understand that; a combination of 28 is to be selected. Because the order is not important, we make use of combination.

Also, because repetition is allowed; different balloons of the same kind can be selected over and over again.

So:

n => 28 + 8-1= 35

r = 28

Selection = ^{35}^C_{28

Selection = \frac{35!}{(35 - 28)!28!}

Selection = \frac{35!}{7!28!}

Selection = \frac{35*34*33*32*31*30*29*28!}{7!28!}

Selection = \frac{35*34*33*32*31*30*29}{7!}

Selection = \frac{35*34*33*32*31*30*29}{7*6*5*4*3*2*1}

Selection = \frac{33891580800}{5040}

Selection = 6724520

Solving (b): At most 12 red balloons

First, we calculate the ways of selecting at least 13 balloons

Out of the 28 balloons, there are 15 balloons remaining (i.e. 28 - 13)

So:

n => 15 + 8 -1 = 22

r = 15

Selection of at least 13 =

At\ least\ 13 = ^{22}C_{15}

At\ least\ 13 = \frac{22!}{(22-15)!15!}

At\ least\ 13 = \frac{22!}{7!15!}

At\ least\ 13 = 170544

Ways of selecting at most 12  =

At\ most\ 12 = Total - At\ least\ 13 --- Complement rule

At\ most\ 12 = 6724520- 170544

At\ most\ 12 = 6553976

Solving (c): At most 8 blue balloons

First, we calculate the ways of selecting at least 9 balloons

Out of the 28 balloons, there are 19 balloons remaining (i.e. 28 - 9)

So:

n => 19+ 8 -1 = 26

r = 19

Selection of at least 9 =

At\ least\ 9 = ^{26}C_{19}

At\ least\ 9 = \frac{26!}{(26-19)!19!}

At\ least\ 9 = \frac{26!}{7!19!}

At\ least\ 9 = 657800

Ways of selecting at most 8  =

At\ most\ 8 = Total - At\ least\ 9 --- Complement rule

At\ most\ 8 = 6724520- 657800

At\ most\ 8 = 6066720

Solving (d): 12 red and 8 blue balloons

First, we calculate the ways for selecting 13 red balloons and 9 blue balloons

Out of the 28 balloons, there are 6 balloons remaining (i.e. 28 - 13 - 9)

So:

n =6+6-1 = 11

r = 6

Selection =

^{11}C_6 = \frac{11!}{(11-6)!6!}

^{11}C_6 = \frac{11!}{5!6!}

^{11}C_6 = 462

Using inclusion/exclusion rule of two sets:

Selection = At\ most\ 12 + At\ most\ 8 - (12\ red\ and\ 8\ blue)

Only\ 12\ red\ and\ only\ 8\ blue\ = 170544+ 657800- 462

Only\ 12\ red\ and\ only\ 8\ blue\ = 827882

At\ most\ 12\ red\ and\ at\ most\ 8\ blue = Total - Only\ 12\ red\ and\ only\ 8\ blue

At\ most\ 12\ red\ and\ at\ most\ 8\ blue =  6724520 - 827882

At\ most\ 12\ red\ and\ at\ most\ 8\ blue =  5896638

3 0
1 year ago
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