Answer:
- P(≥1 working) = 0.9936
- She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.
Step-by-step explanation:
1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...
... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936
2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.
If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.
This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.
_____
My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)
So from 1986 you Subtract total percentage 24.65% an $48 And the answer is a
Answer:
- <em><u> It begins to move toward the right</u></em>
Explanation:
The given information can be summarized in this way:
- First force vector: Fg = - 8N (vertical down)
- Second force vector: Ft = 6N (horizonal right)
- Third force vector: FN = 8N (vertical up)
- Fourth vector: Ff = - 4N (horizontal left)
Following Newton's second law, net force equal mass times acceleration:
- Net force = mass × acceleration
To predict the motion, you apply Newton's second law in each direction (vertical and horizontal)
- <u>Vertical force balance:</u>
Net vertical force = 8N - 8N = 0. This means there is not motion in the vertical direction.
- <u>Horizontal force balance:</u>
Net horizontal force = 6N - 4N = 2N. This means there is a net force of 2N to the right, which lets you predict that the bone starts to accelerate to the right; this is, the bone begins to move toward the right.
Answer:
His 95% confidence interval is (0.065, 0.155).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
His 95% confidence interval is (0.065, 0.155).
