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Ivahew [28]
1 year ago
9

Geometry: Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.

Mathematics
2 answers:
Kazeer [188]1 year ago
6 0

It is given in the question that,

Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.

And

m \angle PQS = 2x+1
\\
m \angle RQS = 4x-15

Since QS bisects angle PQR, therefore

m \angle PQS = m \angle RQS

Substituting the values, we will get

2x+1=4x-15
\\
1+15 = 4x-2x
\\
2x = 16
\\
x = 8

Lisa [10]1 year ago
3 0

Answer:

x = 8

∠PQR = 34°

Step-by-step explanation:

Given: Line QS bisects ∠PQR

  • The measure of ∠PQS = 2x + 1
  • The measure of ∠RQS = 4x - 15

QS is bisector of ∠PQR

So, ∠PQS = ∠RQS

2x + 1 = 4x - 15

4x - 2x = 1 + 15

     2x = 16

      x = 8

∠PQS = 2(8) + 1

          = 16+1

         = 17°

∠RQS = 4x-15

          = 4(8)-15

          = 17°

∠PQR = ∠PQS + ∠RQS

          = 17° + 17°

          = 34°

Hence, The measure of ∠PQR is 34°

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The length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58° to 3
viva [34]

Answer:

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Step-by-step explanation:

Given:

When angle of elevation of the sun changes from 58° to 36° the length of shadow of a pole increases by 90 m.

To find:

Length of pole = ?

Solution:

Kindly refer to the attached image.

\triangle ABC represents the 1st angle of elevation of sun i.e.  58°

\triangle ABD represents the 2nd angle of elevation of sun i.e.  36°

Change in shadow is represented by CD = 90 m

Let height of pole, AB = h m

Let side BC = x m

Now, let us apply tangent rules in \triangle ABC, \triangle ABD one by one:

tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan58^\circ=\dfrac{AB}{BC}\\\Rightarrow tan58^\circ=\dfrac{h}{x}\\\Rightarrow x = 0.624h ..... (1)

tan36^\circ = \dfrac{h}{x+90}

Putting value of x using equation (1):

tan36^\circ = \dfrac{h}{0.624h+90}\\\Rightarrow 0.726\times 0.624h+0.726\times 90 = h\\\Rightarrow h-0.453h =65.34\\\Rightarrow \bold{h = 119.45\ m}

119.45 m is the height of pole.

7 0
2 years ago
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