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QveST [7]
2 years ago
10

Anderson has $50 in his savings account. He deposits $5 every week. His father also deposits $20 into the account every time And

erson mows the lawn. His savings account balance can be shown with the following expression:
50 + 5w + 20m

Part A: Identify a coefficient, a variable, and a constant in this expression. (3 points)

Part B: If Anderson saves for 10 weeks and mows the lawn 2 times, how much will he have in his account? Show your work to receive full credit. (4 points)

Part C: If Anderson had $85 in his savings account, would the coefficient, variable, or constant in the expression change? Why? (3 points)
Mathematics
2 answers:
Sav [38]2 years ago
8 0

Part A: 5 is the coefficient, w is the variable, 50 is the constant

Part B: 10 x 5 = 50 + 2 x 20 = 40+ 50 = $140

Part C: the constant,50,would change and become 85.  Hope this helps :)
mylen [45]2 years ago
3 0
Part A is W and M because those are the coefficient variable and constant.

Part B  10*5=50 ~20*2=40 50+40=90

part c  it would change to 85

I really hope this helps you ^-^

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Step-by-step explanation:

Step 1 :

Let x be the number of points scored by the team.

Given Joe has scored 2 points more than one sixth of the point scored bynthe team

Step 2:

Based on the above given information the equation which gives the points scored by Joe is as follows:

(1/6) x + 2

Given that Joe has scored 10 points, we have

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When we solve the above equation for x , we get the total number of points scored by the team

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Step-by-step explanation:

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Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch
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Answer:

y=\frac{-7t^2+22t-7}{7t-22}

Step-by-step explanation:

We are given that

Initial value problem

y'=(t+y)^2-1, y(3)=4

Substitute the value z=t+y

When t=3 and y=4 then

z=3+4=7

y'=z^2-1

Differentiate z w.r.t t

Then, we get

\frac{dz}{dt}=1+y'

z'=1+z^2-1=z^2

z^{-2}dz=dt

Integrate on both sides

-\frac{1}{z}dz=t+C

z=-\frac{1}{t+C}

Substitute t=3 and z=7

Then, we get

7=-\frac{1}{3+C}

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Substitute the value of C then we get

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y=\frac{-7}{7t-22}-t

y=\frac{-7-7t^2+22t}{7t-22}

y=\frac{-7t^2+22t-7}{7t-22}

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