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Ymorist [56]
2 years ago
10

According to Euclid’s second postulate, how far can the line segment shown be extended in either direction?

Mathematics
2 answers:
Vilka [71]2 years ago
8 0

Answer:

b. not at all

Step-by-step explanation:

• a line goes on forevee in every direction

• a ray continues forever in one direction only

• a segment has a set length and will not extend

PilotLPTM [1.2K]2 years ago
6 0

Answer:

the answer is B. not at all

Step-by-step explanation:

i took on the test... it looked by the same!

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Multiply 8674 x 678 is what
makkiz [27]

Answer:

5880972

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7 0
2 years ago
Select all of the potential solution(s) of the equation 2log5x = log54?
Romashka-Z-Leto [24]

Answer:

jit is good work i am sorry i am doing this but that is how business work

Step-by-step explanation:

also here sorry

4 0
2 years ago
Read 2 more answers
At one gas station, gas costs $2.75 per gallon. Write an equation that relates the total cost, C, to the number of gallons of ga
melisa1 [442]

Answer:

The equation will be:

  • C = 2.75g

Step-by-step explanation:

Given that at one station, gas costs $2.75 per gallon.

Let 'g' be the number of gallons of gas purchases

Let 'C' be the total cost

Thus, the expression for total cost can be generated by multiplying the price per gallon by the number of gallons.

Thus,

C = 2.75g

Therefore, the equation will be:

  • C = 2.75g
6 0
2 years ago
Please help me answer this ASAP! The two-way table shows the number of ninth and tenth graders who prefer going to sporting even
Elis [28]
<h2>Answer</h2>

0.43

<h2>Explanation</h2>

Remember that RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so SumOfAllFrecuencies=6+8=14. Let's replace the values:

RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

RelativeFrecuency=\frac{6}{14}

RelativeFrecuency=0.4285

And rounded to the nearest hundredth:

RelativeFrecuency=0.43

4 0
2 years ago
A website advertises job openings on its website, but job seekers have to pay to access the list of job openings. The website re
nataly862011 [7]

Answer:

The 90% confidence interval would be given by (57.006;62.994)  

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X=60 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=10 represent the population standard deviation  

n=30 represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=10)

The sample mean \bar X is distributed on this way:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.90=0.1,\alpha/2 =0.05 and z_\alpha/2=1.64  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=1.64

Since we have all the values we can replace:

60 - 1.64\frac{10}{\sqrt{30}}=57.006  

60 + 1.64\frac{10}{\sqrt{30}}=62.994  

So on this case the 90% confidence interval would be given by (57.006;62.994)  

5 0
2 years ago
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