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ikadub [295]
2 years ago
8

Calculate the difference between the 1990-1997 average blue crab population and the 1998-2009 average blue crab population predi

ct the average blue crab population for 2010-2020 and explain
Mathematics
1 answer:
Karolina [17]2 years ago
5 0
The difference of the blue crab population From 1990-1997, the average was (800+750)/2 = 775; and from 1989-2009: (350+350)/2 = 350. I predict that from 2010 to 2020 the population will increase to about 500 because it seems to go on trends of increasing and decreasing.
You might be interested in
Consider a set of 7500 scores on a national test whose score is known to be distributed normally with a mean of 510 and a standa
german
\mathbb P(X>600)=\mathbb P\left(\dfrac{X-510}{85}>\dfrac{600-510}{85}\right)=\mathbb P(Z>1.059)\approx0.145

So approximately 14.5% of the scores are higher than 600. This means in a sample of 7500, one could expect to see 0.145\times7500\approx10.86 scores above 600.
5 0
2 years ago
Anyone know the answer??
olga_2 [115]
No. no i do not so yeah.
5 0
1 year ago
a barangay has 1000 individuals and its population doubles every 60 years. Give an exponential model for the barangay's populati
sdas [7]

Answer:

P(t) = 1000e^(0.01155)t

Step-by-step explanation:

Let the population of barangay be expressed according to the exponential formula;

P(t) = P0e^kt

P(t) is the population of the country after t years

P0 is the initial population

t is the time

If barangay has 1000 initially, this means that P0 = 1000

If the population doubles after 60years then;

at t = 60, P(t) = 2P0

Substitute into the formula

2P0 = P0e^k(60)

2 = e^60k

Apply ln to both sides

ln2 = lne^60k

ln2 = 60k

k = ln2/60

k = 0.01155

Substitute k = 0.01155 and P0 into the expression

P(t) = 1000e^(0.01155)t

Hence an exponential model for barangay's population is

P(t) = 1000e^(0.01155)t

7 0
2 years ago
A sociologist wishes to see if it is true that for a certain group of professional women, the average age at which they have the
Vadim26 [7]

Answer:

Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o

Step-by-step explanation:

The explanation of given question is described below:

Here, the test of hypothesis states that

H_o : Mean = 28.6

H_a : Mean\ which\ is\ not\ equals\ 28.6

The test statistic is

Z = \frac{(\bar X - Mean)}{\frac{Population\ standard\ deviation}{vn} }

Z = \frac{(30.06 - 28.6)}{\frac{4.18}{6} }

= 2.1

According to the given data α = 0.05,

So, the major value is

IZ(0.025)I = 1.96

(refer to the standard normal table) .

Finally

Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o

3 0
2 years ago
The table shows the results of four surveys that randomly sampled 30 teenagers about their favorite night to hang out with frien
Pani-rosa [81]

Answer:

46%

Step-by-step explanation:

Because i think so sorry if i get it wrong have a great day!

7 0
1 year ago
Read 2 more answers
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