Answer:
The p-value should be higher than 0.05
Step-by-step explanation:
solution is found below
Answer:
Extrema: relative minimum (1.25,-3.25), relative maximums (3.25,10) and (0,0)
Zeros: (0,0), (2,0), and (4,0)
End behavior: As x approaches infinity, the function approaches negative infinity. As x approaches negative infinity, the function approaches negative infinity.
Intervals of increase and decrease: increasing on (-∞, 0) and (1.25, 3.25), decreasing on (0, 1.25) and (3.25, ∞)
Positive and negative intervals: positive on (2, 4), negative on (-∞, 0), (0, 2), and (4, ∞)
plato answer
Step-by-step explanation:
Solution:
As we are given that f(1) = 0 .
It mean that 
is one of the factor of the given equation.
Remainder theorem can be applied as below:
Hence the factors are (x-1),(x+3) and (x+1).
Hence the correct option is B.
Answer:
Step-by-step explanation:
Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.
A - the first card is 4
B - second card is ace
We have to find probability for
P(A) = no of 4s in the deck/total cards = 
After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it
P(B) = no of Aces in 51 cards/51 = 
Hence
(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin.
<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>
<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>
<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>
<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>
<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>
<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>
<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>
<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>
<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
