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1 year ago

6

use the point-slope equation to identify the slope and the coordinates of a point on the line y – 4 = 1/2 (x – 1). the slope of

the line is . a point on the line is

2 answers:

mihalych1998 [28]1 year ago

7 0

Answer:

The slope of the line is $\dfrac{1}{2}$ and a point on the line is $(1, 4)$

Step-by-step explanation:

The general point slope of line passing through $(x_1,y_1)$ and having slope as m.

$y-y_1=m(x-x_1)$

The given equation of the straight line,

$y-4=\dfrac{1}{2}(x-1)$

Comparing this to the general equation we get the point as $(1, 4)$ and slope as $\dfrac{1}{2}$

Elden [556K]1 year ago

7 0

we know that

The equation of the line into point-slope form is equal to

$y-y1=m(x-x1)$

where

m is the slope

(x1,y1) is the point

In this problem we have

$y-4=\frac{1}{2}(x-1)$

therefore

<u>The slope is equal to</u>

$m=\frac{1}{2}$

<u>The point is equal to</u>

$(1,4)$

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A wheat farmer cuts down the stalks of wheat and gathers them in 200 piles. The 200 gathered piles will be put on a truck. The t

denpristay [2]

Answer:

Check the explanation

Step-by-step explanation:

We want to estimate the total weight of grain on the field based on the data on a simple random sample of 5 piles out of 200. The population and sample sizes are N=200 & n=5 respectively.

1) Let Y_1,Y_2,...,Y_{200} be the weight of grain in the 200 piles and y_1,y_2,...,y_{5} be the weights of grain in the pile from the simple random sample.

We know, the sample mean is an unbiased estimator of the population mean. Therefore,

$\widehat{\mu}=\overline{y}=\frac{1}{5}\sum_{i=1}^{5}y_i=\frac{1}{5}(3.3+4.1+4.7+5.9+4.5)=4.5$

where \mu is the mean weight of grain for all the 200 piles.

Hence, the total grain weight of the population is

$\widehat{Y}=Y_1+Y_2+...+Y_{200}$

= $200\times \widehat{\mu}\: \: \: =200\times 4.5\: \: \: =900\, lbs$

2) To calculate a bound on the error of estimates, we need to find the sample standard deviation.

The sample standard deviation is

S= $\sqrt{\frac{1}{5-1}\sum_{i=1}^{5}(y_i-\overline{y})^2}\: \: \: =0.9486$

Then, the standard error of $\widehat{Y} is$

$\sigma_{\widehat{Y}} =\sqrt{\frac{N^2S^2}{n}\bigg(\frac{N-n}{N}\bigg)}\: \: \:$ =83.785

Hence, a 95% bound on the error of estimates is

$[\pm z_{0.025}\times \sigma_{\widehat{Y}}]\: \: \: =[\pm 1.96\times 83.875]\: \: \: =[\pm 164.395]$

3) Let x_1,x_2,...,x_5 denotes the total weight of the sampled piles.

Mean total weight of the sampled piles is

$\overline{x}=\frac{1}{5}\sum_{i=1}^{5}x_i=45$

The sample ratio is

$r=\frac{\overline{y}}{\overline{x}}=\frac{4.5}{45}$ =0.1 , this is also the estimate of the population ratio R= $\frac{\overline{Y}}{\overline{X}} .$

Therefore, the estimated total weight of grain in the population using ratio estimator is

$\widehat{Y}_R\: \: =r\times 8800\: \: =0.1\times 8800\: \: =880\,$ lbs

4) The variance of the ratio estimator is

var(r)= $\frac{N-n}{N}\frac{1}{n}\frac{1}{\mu_x^2}\frac{\sum_{i=1}^{5}(y_i-rx_i)^2}{n-1} , where \mu_x=8800/200=44lbs$

= $\frac{200-5}{200}\, \frac{1}{5}\: \frac{1}{44^2}\, \frac{0.2}{5-1}=0.000005$

Hence, the standard error of the estimate of the total population is

$\sigma_R=\sqrt{X^2 \: var(r)}\: \: \: =\sqrt{8800^2\times 0.000005}\: \: \:$ =21.556

Hence, a 95% bound on the error of estimates is

$[\pm z_{0.025}\times \sigma_{R}]\: \: \: =[\pm 1.96\times 21.556]\: \: \: =[\pm 42.25]$

8 0

2 years ago

Read 2 more answers

A farm can harvest 120 pounds of carrots per acre of land. Each crate can hold 24 pounds of carrots. If a farmer owns 4.8 acres

Shtirlitz [24]

Answer:

The farmer needs 24 crates to hold the carrots.

Step-by-step explanation:

To determine how many crates the farmer needs to hold the carrots, knowing that his farm has 4.8 acres of land, where he can harvest 120 pounds per acre, and that each crates can hold up to 24 pounds of carrots, the following calculation must be performed:

(4.8 x 120) / 24 = X

576/24 = X

24 = X

Thus, the farmer needs 24 crates to hold the carrots.

6 0

1 year ago

In order to produce 100 oatmeal cookies, Goodie Cookie Co. incurs an average total cost of $0.25 per cookie. The company’s margi

amm1812

Answer:

Option D : $20

Step-by-step explanation:

The average total cost to produce 100 oatmeal cookie = $0.25 per cookie.

So, total cost for 100 cookies will be = $0.25\times100=25$ dollars

The company’s marginal cost is constant at $0.10 for all oatmeal cookies produced.

When 50 cookies are produced, the marginal cost will be = $0.10\times50=5$ dollars

The total cost to produce 50 oatmeal cookies = $25-5=20$ dollars

Hence, option D is correct.

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2 years ago

Patrick owns an apartment building. He knows that the money he earns in a month depends on the rent he charges. The relationship

belka [17]

E=13,000 and<span>E=1/50R(1650-R)</span>

<span>
</span>

<span />0.02R(1650-R)=13000

<span>(0.02R)(1650)-0.02R²=13000</span>

<span /><span>0.02R²-33R+13000=0</span>

<span>R2-1650R+650000=0</span>

<span>SOLVE W QUAD FORMULA
</span>

7 0

1 year ago

What equation can be used to solve for angle C?

matrenka [14]

The formula for calculating the total interior angle in a regular polygon is given as:

total interior angle = (n -2) 180

where n is the number of sides and since there are sides:

total interior angle = 360°

To get this angle, we know that it is the summation of all angles:

360° = angle A + angle C + angle B + angle D ---> 1

Looking closely, we can see that segments BC and AD are parallel which means that:

angle A + angle C = angle B + angle D ---> 2

Substituting equation 2 to 1:

360 = 2 (angle A + angle C)

angle A + angle C = 180

(x + 16) + (6x – 4) = 180

Answer:

B

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2 years ago