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Allisa [31]
1 year ago
10

The diagram below shows 5 identical bowls stacked one inside the other. The height of 1 bowl is 2 inches. The height of 5 bowls

is 5 inches.
Part A: Write an equation using x and y to find the height of a stack of bowls based on any number of bowls.


Part B: Describe what the x and y variable represent.


Part C: Use the equation from Part A to find the number of bowls if the height of the stacked bowls is 12.5 inches.
Mathematics
1 answer:
padilas [110]1 year ago
7 0

(Bowls, Height) (1, 2)  (5,5)

Slope is (5-2)/(5-1) = 3/4 inch
y = (3/4)x + b
(2) = (3/4)(1) + b
(2)-(3/4) = b

B=1.25.  Y= 0.75*x + 1.25. 

Part B
X is the number of bowls in the stack and Y is the corresponding height of the stack.

 

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Of 1,050 randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wage ea
garik1379 [7]

Answer:

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

Step-by-step explanation:

We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.

We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.26.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26*0.74}{160}}\\\\\\ \sigma_p=\sqrt{0.0012}=0.0347

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.0347=0.068

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.26-0.068=0.192\\\\UL=p+z \cdot \sigma_p = 0.26+0.068=0.328

The 95% confidence interval for the population proportion is (0.192, 0.328).

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

3 0
2 years ago
A customer visiting the suit department of a certain store will purchase a suit with probability .22, a shirt with probability .
BigorU [14]

Answer:

a) The probability that he doesnt but any items is 0.49

b) He buys exactly 1 of those items with probability 0.28

Step-by-step explanation:

lets call su the event that the customer purchases a suit, sh the event that teh customer purchases a shirt and t the event that the customer purchases a tie.

Remembe that for events A, B and C we have that

P(A U B) = P(A) + P(B) - P(A ∩ B)

P(A U B U C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

Also, we are given that

P(su) = 0.22

P(sh) = 0.3

p(t) = 0.28

p(su ∩ sh) =  0.11

P(su ∩ t) = 0.14

P(sh ∩ t) = 0.1

P(sh ∩ t ∩ su) = 0.06

The event that he doesnt buy any item has as complementary event su ∪ sh ∪ t, therefore

P( he doesnt but any items) = 1-P(su U sh U t) =

1-( P(su) + p(sh) + p(t) - P(su ∩ sh) - p(su∩t) - p(sh∩t) + p(su∩sh∩t) ) =

1-(0.22+0.30+0.28-0.11-0.14-0.1+0.06) = 1-0.51 = 0.49

b) The probability that he buys at least 2 items is equal to

p(su ∩ t) + p(su ∩ sh) + p(sh ∩ t) -2 p(su ∩ t ∩ sh) (because we are counting the triple intersection 3 times, so we need to remove it twice)

This number is

0.14+0.11+0.1-2*0.06 = 0.23

Thus, the probability that he buys exactly one item can be computed by substracting from one the probability of the complementary event : she buys 2 or more or non items

P(he buys exactly one item) = 1- ( p(he buys none items) + p(he buys at least 2) ) = 1- 0.49-0.23 = 0.28

7 0
2 years ago
Read 2 more answers
In a group of 90 students, 65 watch rugby, 71 play a sport and 15 do neither.
Dimas [21]

Answer:

\frac{14}{75} probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.

Step-by-step explanation:

"Find the probability that a student chosen at random from those who play a sport  does not watch rugby."

90-15= 75 students either play a sport OR watch rugby

65+71-75=

136-75=

61 people play a sport AND watches rugby

14 people play a sport and DOES NOT watch rugby

\frac{14}{75} is the probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.

4 0
1 year ago
In 7 days, Mario cooked 98 pounds of spaghetti. Each day after the first, he cooked 2 more pounds than he cooked than the day be
yan [13]

so I need to do a list of numbers like this:

98, 100, 102, 104, 106, 108, 110.

104 is the median number

add 98+100+102+104+106+108+110=728

divide by seven 728 / 7 = 104

so the difference between the median 104 and the avarage 104 is 0 they are

104=104


hope this helps

7 0
2 years ago
What is the balance on an amortized loan of $110,000 after the first payment if the interest rate is 5.5% with a monthly P&I
marishachu [46]
The interest due on the first payment is
.. I = Prt
.. I = 110,000*.055*(1/12)
.. I = 504.17

Then the decrease in principal resulting from the first payment is
.. 568.00 -504.17 = 63.83
and the new balance is
.. $110,000.00 -63.83 = $109,936.17
4 0
2 years ago
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