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charle [14.2K]
2 years ago
7

Tina Avallone and her husband are buying a $219,000 home. Their annual housing expenses are: mortgage payments, $15,400; real es

tate taxes, $3,600; annual homeowner’s insurance premium, $1,895; maintenance on the home, $3,200; and utilities, $3,980. The lost interest on the down payment is $1,001 and the tax savings is $1,976. What is their average monthly expense?
Mathematics
1 answer:
joja [24]2 years ago
3 0

Answer:

the answer is actually is $2,258.33

Step-by-step explanation:

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Which table of ordered pairs represents a proportional relationship?​
34kurt

Answer:

its c

Step-by-step explanation:

5 0
2 years ago
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Pierce currently has $10,000. What was the value of his money five years ago if he has earned 5 percent interest each year?
tia_tia [17]
The first answer is correct, if you go back by 5% each year you will see that.

4 0
2 years ago
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Enter the values for the variables that give the correct simplified expressions, x = ≥ 0.
ELEN [110]

Answer:

b= 2x²; c = 4; 3 = 3 ; g = 6x

Step-by-step explanation:

\textbf{(1)}\\\sqrt{50{x}^{2} } = \sqrt{25\times2x^{2}} = 5\times \mathbf{\sqrt{2x^{2}}}\\\textbf{b = 2x}^{2}\\\\\textbf{(2)}\\\sqrt{32x} = \sqrt{16 \times 2x} = \mathbf{4}\times \sqrt{2x}\\\textbf{c = 4}\\\\\textbf{(3)}\\\sqrt{18n} = \sqrt{9 \times 2n} = \mathbf{3}\times \sqrt{2n}\\\textbf{e = 3}\\\\\textbf{(4)}\\\sqrt{72x^{2}} = \sqrt{36 \times 2x^{2}} = 6\times \sqrt{2} \times x\\= \mathbf{6x}\sqrt{2}\\\textbf{g = 6x}

3 0
2 years ago
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Consider the function f(x) = x3 − 4x2 + 2. Calculate the limit of the difference quotient at x0 = 3 for f(x).
m_a_m_a [10]
<h2>Part 1.</h2>

Answer: \boxed{f'(x)=3x^2-8x}

The limit of the difference quotient is simply the derivative, so we can express this as follows:

f'(x)=\underset{\Delta x\rightarrow0}{lim}\frac{\triangle y}{\Delta x}=\frac{f(x+\Delta x)-f(x)}{\Delta x}

So our function is:

f(x)=x^3-4x^2+2

Taking the derivative, we have:

f'(x)=3x^2-8x

So the correct option is:

\boxed{f'(x)=3x^2-8x}

<h2>Part 2.</h2>

Answer: \boxed{y=3x-16}

The equation of the line that passes through the same point can be found as:

y-y_{0}=m(x-x_{0})

Where x_{0}=3, so we need to find y_{0}. Plug in that x-value in the function we have:

y_{0}=f(3)=(3)^3-4(3)^2+2 \\ \\ y_{0}=-7 \\ \\ \\ So \ the \ point \ is: \\ \\ P(x_{0},y_{0})=(3,-7)

And the slope is:

m=f'(3)=3(3)^2-8(3) \\ \\ m=3

Then, the equation of the line is:

y-(-7)=3(x-3) \\ \\ \therefore y+7=3x-9 \\ \\ \boxed{y=3x-16}

<h2 /><h2>Part 3.</h2>

Answer: Shown below

As you can see below, the graph of the function of f is continuous. This is so because we have plotted a polynomial function whose domain is the set of all real numbers. So the function is defined at the point P(3,-7), so the derivative exists at this point, hence we can calculate a tangent line there. In conclusion, we get the graph shown below. The blue line is the tangent line while the red curve is the graph of f

3 0
2 years ago
you have 5814 meters of rope that you need to cut into 27 meters sections. How many 27 meter section of rope will you be able to
Marta_Voda [28]

Answer:

215 sections of 27 meters of rope will be created and 9 meters will be left as waste

Step-by-step explanation:

A rope that is 5814 meters long needs to be cut into 27 sections

The number of 27 meter sections of rope that can be created can be calculated by dividing 5814 by 27

= 5814/27

= 215 remainder 9

Hence 215 sections of rope will be created and 9 meters of rope will be left as waste

3 0
2 years ago
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