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2 years ago

What is the additive identity of the complex number 14 + 5i?

Mathematics

2 answers:

Naddika [18.5K]2 years ago

7 0

Answer: B) 0

Step-by-step explanation:

1. When you add complex numbers you must add the whole parts and then the imaginary parts.

2. One of the properties of complex numbers is called "Additive identity" which is represented by:

$0+0i$

3. Then, for the complex number $14+5i$ , you have:

$(14+5i)+(0+0i)=(14+0)+(5+0)i=14+5i$

4. Therefore, the answer is the option B.

iVinArrow [24]2 years ago

4 0

Answer:

The answer is B. 0

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Read 2 more answers

A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

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