Answer:
Compatible width of rectangular banquet hall could be 90 feet approximately.
Step-by-step explanation:
Given
Area of a rectangular banquet hall = 7400 square feet
Length of rectangular banquet hall = 82 feet
We need to calculate width of the rectangular banquet hall.
Now Area of rectangle is equal to length times width.
Framing in equation form we get;

Substituting the given values we get;

Now by definition of Compatible numbers which state that:
"Compatible numbers are the numbers that are easy to add, subtract, multiply, or divide mentally. Compatible numbers are close in value to the actual numbers that make estimating the answer and computing problems easier."
Now By Using width as 90 feet and length as 82 feet we get area as 7380 sq ft. which is closet to actual area which is 7400 sq ft.
Hence we can say compatible width could be 90 feet approximately.
Brian has 39 cards and Wesley has 48 cards
Step-by-step explanation:
Let w be the number of cards Wesley has
and
b be the number of cards Brian has
Then

Putting w = 2b-30 in equation 1

Dividing both sides by 3

Putting b=39 in equation 2

Hence,
Brian has 39 cards and Wesley has 48 cards
Keywords: Linear equations, variables
Learn more about linear equations at:
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Volume = 1/3 * area of the base * height
75 = 1/3 * 5^2 * h
h = 75 * 3 / 25 = 3*3 = 9 feet answer
Answer:
StartFraction 2 Over h EndFraction = StartFraction 3 Over m EndFraction
StartFraction 2 Over n EndFraction = StartFraction 3 Over h EndFraction
StartFraction 2 Over h EndFraction = StartFraction h Over n EndFraction
Startfraction 2 Over h EndFraction = StartFraction h Over 3 EndFraction
Step-by-step explanation: