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Kay [80]
2 years ago
7

What is the quotient? Negative StartFraction 3 over 8 EndFraction divided by negative one-fourth WILL GIVE BRAINLIEST

Mathematics
1 answer:
Alisiya [41]2 years ago
3 0

Answer:

Im not too sure given yopur formatting, but I believe you meant this: -((3/8)/(-1/4))

therfore, the answer is: 3/2

Step-by-step explanation:

You can seperate the two fractions as 3/8 divided by -1/4, which is equal to 3/8 * 4/-1, simply multiply across to get 12/-8, which simplifies to -3/2. Flip the sign to get 3/2

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For several hours you watch a group playing dice on the street and you notice that the owner of the dice often wins. do you conc
Alenkinab [10]
The owner is most likely cheating because it is usually a 50|50 chance of winning. But, you usually only get 50, and win a bit less and loose more. So, he is most likely cheating. (Hope this helped  :D)
8 0
2 years ago
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A. Show one pair of corresponding points and two pairs of corresponding sides in the original polygon and its copy. B. what scal
Lera25 [3.4K]

Answer:

Step-by-step explanation:

(A).Two corresponding sides of the given figures will be,

AB and DE

BC and EF

Similarly one pair of corresponding points will be,

A and D.

(B). Since large figure has been scaled to the smaller image,

Scale factor = \frac{\text{Side of the image}}{\text{Side of the actual figure}}

                    = \frac{\text{AB}}{\text{DE}}

                    = \frac{0.5}{2}

                    = 0.25

Therefore, scale factor will be 0.25.

6 0
2 years ago
Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll
JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}

So, the possibility of getting a total of 7 = \frac{6}{36}=\frac{1}{6}

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = \frac{2}{36} = \frac{1}{18}

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = \frac{28}{36} = \frac{7}{9}

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11

\frac{11}{3}+\frac{11}{3}-\frac{77}{9}

\frac{22}{3}-\frac{77}{9}

\frac{66-77}{9}

-\frac{11}{9}

-1.22

Therefore the expected payoff for this game is -$1.22.

4 0
2 years ago
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MatroZZZ [7]

Answer:

0

0.693

1.386

graph A

Step-by-step explanation:

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