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Ivenika [448]
1 year ago
15

Aiden can afford a $280-per-month car payment. If he is being offered a 4-year car loan with an APR of 1.8%, compounded monthly,

what is the value of the most expensive car he can afford?
A.13,439.51
B.13,390.73
C.12,958.20
D.13,435.06
Mathematics
1 answer:
brilliants [131]1 year ago
7 0
Use the formula of the present value of annuity ordinary.
The formula is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv present value?
PMT payment per month 280
R interest rate 0.018
k compounded monthly 12
T time 4years
Pv=280×((1−(1+0.018÷12)^(−12
×4))÷(0.018÷12))
=12,958.20

It's c
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Circular tracts of land with diameters 900 meters, 700 meters and 600 meters are tangent to each other externally. There are hou
Rudik [331]

Answer:

\alpha=69.28^o

\beta=61.26^o

\gamma=49.46^o

<em />A=227980.26\ m^2<em />

Step-by-step explanation:

<u>Triangle Solving</u>

If we had a triangle will its three sides of known length, we can solve for the rest of the parameters of the triangle, i.e. the area, perimeter and internal angles.

The three circles have diameters 900 m, 700 m and 600 m and are tangent to each other externally. The distances from their centers (where houses are located) are the sum of each pair of the radius of the circles. Thus, the sides of the triangle are

x=450+350=800

y=450+300=750

z=350+300=650

The internal angles can be computed by using the cosine's law

x^2=y^2+z^2-2yzcos\alpha

y^2=x^2+z^2-2xzcos\beta

z^2=x^2+y^2-2xycos\gamma

Where \alpha, \beta and \gamma are the opposite angles to x, y and z respectively. Solving for each one of them:

\displaystyle cos\alpha=\frac{y^2+z^2-x^2}{2yz}

\displaystyle cos\alpha=\frac{750^2+650^2-800^2}{2\cdot 750\cdot 650}

cos\alpha=0.3538

\alpha=69.28^o

Similarly

\displaystyle cos\beta=\frac{x^2+z^2-y^2}{2xz}

\displaystyle cos\beta=\frac{800^2+650^2-750^2}{2\cdot 800\cdot 650}

cos\beta=0.4808

\beta=61.26^o

The other angle is computed now

\displaystyle cos\gamma=\frac{x^2+y^2-z^2}{2xy}

\displaystyle cos\gamma=\frac{800^2+750^2-650^2}{2\cdot 800\cdot 750}

cos\gamma=0.65

\gamma=49.46^o

The area can be found by

\displaystyle A=\frac{1}{2}x.y.sin\gamma

\displaystyle A=\frac{1}{2}\cdot 800\cdot 750\cdot sin49.46^o

A=227980.26\ m^2

8 0
2 years ago
-79 = 7w + 3(4w – 1)​
vladimir1956 [14]

Hello! The answer to your question would be as followed:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    -79-(7*w+3*(4*w-1)=0

 -79 -  (7w +  3 • (4w - 1))  = 0

Pulling out like terms :

  Pull out like factors :

  -19w - 76  =   -19 • (w + 4)

 -19 • (w + 4)  = 0

Equations which are never true :

      Solve :    -19   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

     Solve  :    w+4 = 0

Subtract  4  from both sides of the equation :

                     w = -4

                  w = -4

5 0
2 years ago
Read 2 more answers
A rainwater collection system uses a cylindrical storage tank with a diameter of
elixir [45]

Answer:

157079.6

Step-by-step explanation the formula to find volume of a cylinder is pi radius squared(half of diameter) times height.

6 0
1 year ago
Read 2 more answers
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
babunello [35]

For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

  • <em>g: acceleration of gravity </em>
  • <em>vo: initial speed </em>
  • <em>h0: initial height </em>

For the first body:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second body:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

By the time both bodies have the same height we have:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rewriting we have:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

Clearing time:

t = 29 (\frac {12} {19})\\t = 18.31s

Answer:

 it takes 18.31s for the two window washers to reach the same height

6 0
2 years ago
Read 2 more answers
Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon. Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbo
Svetllana [295]

ENter you name for more info:________________

5 0
2 years ago
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