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Usimov [2.4K]
2 years ago
12

The parent function f(x) = x3 is represented by graph A. Graph A is transformed to get graph B and graph C. Write the functions

represented by graph B and graph C. Graph B represents the function g(x) = . Graph C represents the function h(x) = .

Mathematics
2 answers:
vesna_86 [32]2 years ago
5 0

The parent function f(x) = x^3 is represented by graph A.

The graph B is shifted 2 units down

If graph is shifted down then we put negative

We subtracted 2 at the end

so the function represented by Graph B is

f(x) = x^3 - 2

Now we look at the graph C

The graph C is stretched vertically

In graph A we have point (1,1)

In graph C  we have point (1,2)

It means y is multiplied by 2

So the graph C is stretched vertically by 2 units

So for graph C f(x) = 2x^3



Alekssandra [29.7K]2 years ago
4 0
Graph B represents the function g(x)=x^3-2 Graph C represents the function h(x)=2x^3
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The solution would be like this for this specific problem:

sin(θ°) = √(2)/2 

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θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ 

360°*0 + 45° = 45° 
360°*0 + 135° = 135° 
360°*1 + 45° = 405° 

<span>sin(225°) = -√(2)/2

</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta cannot be 225 degrees.

4 0
2 years ago
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9. Your school offers two English classes, three math classes and three
s2008m [1.1K]
There are 12 different ways to organize your schedule

There are 2 English classes
There are 3 math classes
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Take 2x3x3 and you get 12
5 0
2 years ago
A print shop purchases a new printer for $25,000. The equipment depreciates at a rate of 5% each year. The relationship between
Pani-rosa [81]

Answer:

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

Step-by-step explanation:

Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

y(x) = 25,000*0.95^x

In the first year the value of the printer is:

y(1) = 25,000*0.95^1 = 23,750

On the second year the value of the printer is:

y(2) = 25,000*0.95^2 = 22,562.5\\

On the third year the value of the printer is:

y(3) = 25,000*0.95^3 = 21,434.38\\

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

5 0
2 years ago
A car was purchased for $25,000. Research shows that the car has an average yearly depreciation rate of 18.5%. Create a function
vitfil [10]

Answer:

V(t) = 25000 * (0.815)^t

The depreciation from year 3 to year 4 was $2503.71

Step-by-step explanation:

We can model V(t) as an exponencial function:

V(t) = Vo * (1+r)^t

Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.

We have that Vo = 25000, r = -18.5% = -0.185, so:

V(t) = 25000 * (1-0.185)^t

V(t) = 25000 * (0.815)^t

In year 3, we have:

V(3) = 25000 * (0.815)^3 = 13533.58

In year 4, we have:

V(4) = 25000 * (0.815)^4 = 11029.87

The depreciation from year 3 to year 4 was:

V(3) - V(4) = 13533.58 - 11029.87 = $2503.71

7 0
2 years ago
The Green family is a family of six people. They have used 4,885.78 gallons of water so far this month. They cannot exceed 9,750
prohojiy [21]

Answer:

The inequality is  6x+4,885.78\leq 9,750.05

x\leq 810.71\ gal

Step-by-step explanation:

Let

x -----> amount of water that can be used by only one family member for the rest of the month

we know that

6x+4,885.78\leq 9,750.05

Solve for x

Subtract 4,885.78 both sides

6x\leq 9,750.05-4,885.78

6x\leq 4,864.27

Divide by 6 both sides

x\leq 4,864.27/6

x\leq 810.71\ gal

3 0
2 years ago
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