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zepelin [54]
2 years ago
15

I WILL GIVE BRAINLEST PLZ HELP!!!

Mathematics
2 answers:
adell [148]2 years ago
7 0

Step-by-step explanation:

The Slope is calculated as the change in y over the change in x so you would need to do 5- (-5) which turns the negative sign to a positive making it 5+5=10 and the same thing with the 2s 2-(-2)=4 so the answer would be 10/4 or 5/2. Willa did the reciprocal.

if it's a multiple chose then the answer is b

hope this helps

ziro4ka [17]2 years ago
5 0

Answer:

here is the answer

Step-by-step explanation:

You might be interested in
In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist
vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

τ = 5 seconds..............(3)

Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

= 0.04e-0.5 = 0.04/√e

= 0.04/1.6487

= 0.0292

Thus, Cov(X, Y) =0.029.

5 0
1 year ago
What is the length of the hypotenuse of the triangle below?
liberstina [14]

Answer:

\boxed{B. Hypotenuse = 10}

Step-by-step explanation:

By applying <em>Pythagoras theorem</em> we can find hypotenuse of a right angle triangle.

Side of right angle triangle (a) = 5√2 cm

Side of right angle triangle (b) = 5√2 cm

Hypotenuse² = a² × b²

{Hypotenuse}^{2}  =  {(5 \sqrt{2} )}^{2}  \times  {(5 \sqrt{2} )}^{2}  \\  \\  {Hypotenuse}^{2}  = (25 \times 2) + (25 \times 2)\\  \\  {Hypotenuse}^{2}  = 50 + 50\\  \\ {Hypotenuse}^{2}  = 100\\  \\   {Hypotenuse}^{ \cancel{2}}  =  {10}^{ \cancel{2}}  \\  \\   Hypotenuse = 10

7 0
1 year ago
Read 2 more answers
If h:k = 2:5, x:y=3:4 and 2h+x:k+2y = 1:2, find the ratio h-x: k-y.​
fenix001 [56]

Given:

h:k=2:5,x:y=3:4,2h+x:k+2y=1:2

To find:

h-x:k-y

Solution:

We have, h:k=2:5 and x:y=3:4.

Let the values of h and k are 2a and 5a respectively.

Let the values of x and y are 3b and 4b respectively.

We have,

2h+x:k+2y=1:2

It can be written as

\dfrac{2h+x}{k+2y}=\dfrac{1}{2}

\dfrac{2(2a)+(3b)}{5a+2(4b)}=\dfrac{1}{2}

\dfrac{4a+3b}{5a+8b}=\dfrac{1}{2}

2(4a+3b)=1(5a+8b)

On further simplification, we get

8a+6b=5a+8b

8a-5a=8b-6b

3a=2b

a=\dfrac{2b}{3}

Now,

h-x:k-y=\dfrac{h-x}{k-y}

h-x:k-y=\dfrac{2-3b}{5a-4b}

h-x:k-y=\dfrac{2\times \dfrac{2b}{3}-3b}{5\times \dfrac{2b}{3}-4b}

h-x:k-y=\dfrac{\dfrac{4b}{3}-3b}{\dfrac{10b}{3}-4b}

On further simplification, we get

h-x:k-y=\dfrac{\dfrac{4b-9b}{3}}{\dfrac{10b-12b}{3}}

h-x:k-y=\dfrac{-5b}{-2b}

h-x:k-y=\dfrac{5}{2}

h-x:k-y=5:2

Therefore, the ratio h-x:k-y is 5:2.

8 0
1 year ago
The building site is 90 metres long and 45 metres wide. What is the area of the site?
Lapatulllka [165]

Answer:

The answer would be 4050

Step-by-step explanation:

A=wl

A=45*90

A=4050

5 0
2 years ago
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
2 years ago
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