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Nady [450]
1 year ago
15

Tom takes exactly 30 minutes to rake a lawn and his son Mike takes exactly 60 minutes to rake the same lawn. If Tom and Mike dec

ide to rake the lawn together, and both work at the same rate that they did previously, how many minutes will it take them rake the lawA. 16
b. 20


c. 36


d. 45


e. 90
Mathematics
1 answer:
____ [38]1 year ago
6 0

Answer:

b) 20 minutes

Step-by-step explanation:

Tom=0.5Mike

in 15 minutes, Tom will have done 1/2 of the lawn

in 15 minutes, Mike will have done 1/4 of the lawn

in 15 minutes, they will have done 3/4 of the lawn

15/3=5 minutes for 1/4 of the lawn to be done

5x4=20 minutes for the entire lawn

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297,060 / 0.0004839 =<br><br> Answer in Scientific Notation it Standard Notation
Valentin [98]

Answer:

6.1389 x 10^8

Step-by-step explanation:

3 0
1 year ago
Sonya and Isaac are in motorboats located at the center of a lake. At time t=0, Sonya begins traveling south at a speed of 36 mp
Rashid [163]

Answer:

the speed btn sonya and issac would make a right angled trangle hence easy 2 solve through pythogoras

{36}^{2}  +  {27}^{2}  = 2025

then find the

\sqrt[?]{?}

hence get 45

since it was 12 mins we need 2 multiply by 12

hence

45 \times 12 = 540

Therefore it's 540mph

6 0
1 year ago
Here is a scale drawing of a window frame that uses a scale of 1 cm to 6 inches.Create another scale drawing of the window frame
Tresset [83]

Answer:

Step-by-step explanation:

Below is the rectangle in the attachment.

Current scale:

1 cm : 6 inches

If the dimensions of the rectangle is:

Length = a cm

Width = b cm

Using the scale:

Length = a × 6 inches

Width = b × 6 inches

Using the same dimensions of the rectangle is:

Length = a cm

Width = b cm

Using the scale:

Length = a × 12 inches

Width = b × 12 inches

Note that there is an enlargement of the rectangle to form the new rectangle. The length and width of new rectangle drawn will be 2 × the length and width of the rectangle seen below.

8 0
1 year ago
AC CE and D is the midpoint of CE. IF CE 10x + 18, DE =7x -1, and BC = 9x - 2, find AB, AB =
Anastasy [175]

Answer:

<h3>      If you mean: AC=CE, the answer is:  AB = 24</h3>

Step-by-step explanation:

D is the midpoint of CE, then

CD = DE = 0.5CE = 0.5(10x+18) = 5x + 9

So:   5x + 9 = 7x - 1

            -9          -9

        5x  =  7x - 8

        -7x      -7x

       -2x  =  -8

      ÷(-2)       ÷(-2)        

          x  =  4

AC = CE = 10x + 18 = 40 + 18 = 58

BC = 9x - 2 = 36 - 2= 34

AB = AC - BC = 58 - 34 = 24

4 0
2 years ago
Monica has a bag of marbles. There are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick
natima [27]

Answer:

\frac{7}{64}\approx 0.11

Step-by-step explanation:

We have been given that there are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick two marbles out of the bag replacing the first marble before picking the second marble.

Since Monica will replace the first marble before picking the second marble, therefore, probability of both events will be independent and probability of occurring one event will not affect the probability of second event's occurring.          

Since the probability of two independent compound events is always the product of probabilities of both events.

P(\text{A and B})=P(A)*P(B)

Now let us find probability of picking a red marble out of 16 (4+7+5) marbles.

P(Red)=\frac{\text{Total red marbles}}{\text{Total marbles}}

P(Red)=\frac{4}{16}

Probability of picking blue ball out of 16 (4+7+5) marbles:

P(Blue)=\frac{\text{Total blue marbles}}{\text{Total marbles}}

P(Blue)=\frac{7}{16}

Now let us find probability of Monica picking a red and then a blue marble.

P(\text{Red and Blue})=\frac{4}{16}\times \frac{7}{16}

P(\text{Red and Blue})=\frac{1}{4}\times \frac{7}{16}

P(\text{Red and Blue})=\frac{7}{4*16}

P(\text{Red and Blue})=\frac{7}{64}

P(\text{Red and Blue})=0.109375\approx 0.11

Therefore, the probability of picking a red and then blue marble is \frac{7}{64}\approx 0.11.  

7 0
1 year ago
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