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Sedaia [141]
2 years ago
10

A group of kids just finished trick-or-treating. The number of pieces of candy collected by each of the 5 kids

Mathematics
1 answer:
NemiM [27]2 years ago
6 0

Answer:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808

And the answer for this case would be :

s= 3.81 after round the value

Step-by-step explanation:

We have the following data set given:

31, 33, 36, 41, 34

If we want to find the standard deviation we need to find first the sample mean with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = \frac{31+33+36+41+34}{5}= \frac{175}{5}= 35

Now we can find the sampel deviation with this formula:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808

And the answer for this case would be :

s= 3.81 after round the value

You might be interested in
Candidate A is facing two opposing candidates in a mayoral election. In a recent poll of 300 residents, 98 supported candidate B
babymother [125]

Answer:

[0.4235, 0.5365]

Step-by-step explanation:

Data given and notation  

n=300 represent the random sample taken    

X=300-98-58=144 represent the people that support the candidate A in the sample

\hat p=\frac{144}{300}=0.48 estimated proportion of people that support the candidate A in the sample

\alpha=0.05 represent the significance level

Confidence =0.95 or 95%

p= population proportion of people that support the candidate A.

Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.48 - 1.96 \sqrt{\frac{0.48(1-0.48)}{300}}=0.4235

0.48 + 1.96 \sqrt{\frac{0.48(1-0.48)}{300}}=0.5365

And the 95% confidence interval would be given (0.4235;0.5365).

0.4235 \leq p \leq 0.5365

8 0
2 years ago
A baby otter was born 3/4 of a month early. At birth it's weight was 7/8 kilograms which is 9/10 kilogram less than the average
Assoli18 [71]

Answer:

The average weight of new born otter was, 1\frac{31}{40}

Step-by-step explanation:

Let average weight of new born otter be x.

As per the given statement: At birth it's weight was 7/8 kilograms which is 9/10 kilogram less than the average weight of a new born otter in the aquarium

"\frac{9}{10} kg less than average weight of a new born otter" means x-\frac{9}{10}

As per the given information, we have;

\frac{7}{8} = x -\frac{9}{10}

Add  \frac{9}{10} both sides, we have;

\frac{7}{8} + \frac{9}{10} = x

Take LCM of 8 and 10 is, 40

⇒\frac{35+36}{40}=x

Simplify:

x = \frac{71}{40} = 1\frac{31}{40}

Therefore, the average weight of new born otter was, 1\frac{31}{40}




6 0
2 years ago
Read 2 more answers
In a data set with a range of 55.4 to 105.4 and 400 observations, there are 176 observations with values less than 86. Find the
IrinaVladis [17]

<u>ANSWER: </u>

In a data set with a range of 55.4 to 105.4 and 400 observations.86 lies in the 49th percentile.

<u>SOLUTION: </u>

Given, in a data set with a range of 55.4 to 105.4 and 400 observations.

There are 176 observations below the value of 86, and we need to find the percentile for 86.

We know that, percentile formula = \frac{\text {number of observations below the required number}}{\text {total number of observations}} \times 100

Percentile of 86 = \frac{176}{400} \times 100

Since, we cancelled 400 with 100 we get 4 , hence above expression becomes,

=\frac{176}{4} = 49

So, percentile of 86 = 49

Hence, 86 lies in the 49th percentile.  

5 0
2 years ago
3.52 A coin is tossed twice. Let Z denote the number of heads on the first toss and W the total number of heads on the 2 tosses.
Rufina [12.5K]

Answer:

a)  The joint probability distribution

P(0,0) = 0.36, P(1,0) = 0.24,   P(2,0) = 0,   P(0,1) = 0,  P(1,1) = 0.24,  P(2,1)= 0.16

b)  P( W = 0 ) = 0.36,    P(W = 1 ) = 0.48,  P(W = 2 ) = 0.16

c) P ( z = 0 ) = 0.6

  P ( z = 1 ) = 0.4

Step-by-step explanation:

Number of head on first toss = Z

Total Number of heads on 2 tosses = W

% of head occurring = 40%

% of tail occurring = 60%

P ( head ) = 2/5 ,    P( tail ) = 3/5

<u>a) Determine the joint probability distribution of W and Z </u>

P( W =0 |Z = 0 ) = 0.6         P( W = 0 | Z = 1 ) = 0

P( W = 1 | Z = 0 ) = 0.4        P( W = 1 | Z = 1 ) = 0.6

P( W = 1 | Z = 0 ) = 0           P( W = 2 | Z = 1 ) = 0.4

The joint probability distribution

P(0,0) = 0.36, P(1,0) = 0.24,   P(2,0) = 0,   P(0,1) = 0,  P(1,1) = 0.24,  P(2,1)= 0.16

<u>B) Marginal distribution of W</u>

P( W = 0 ) = 0.36,    P(W = 1 ) = 0.48,  P(W = 2 ) = 0.16

<u>C) Marginal distribution of Z ( pmf of Z )</u>

P ( z = 0 ) = 0.6

P ( z = 1 ) = 0.4

8 0
2 years ago
O is the centre of the circle, EF is a tangent, angle BCE=28 degrees, angle ACD=31 degrees.
Yuki888 [10]

Answer:

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

a. because angle between tangent and chord is equal to the angle(s) in alternate segment.

b. because angles in triangles add up to 180˚, 180-28=152 and because isosceles triangle, 152/2=76˚

c. because angles in triangles add up to 180˚ and opposite angles in a cyclic quadrilateral add up to 180˚, 31+76=107, 180-107=73, 73-28=45, angles in triangle so 180-(31+45)=104˚

d. 28*2=56˚ because angles at circumference are half angles at centre

4 0
2 years ago
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