A popular chain of superstores made 3.0479×108 dollars in profit last year. One particular store in the chain made 2.102×106 dol
1 answer:
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I suppose
The vectors that span form a basis for
if they are (1) linearly independent and (2) any vector in
can be expressed as a linear combination of those vectors (i.e. they span
).
- Independence:
Compute the Wronskian determinant:
The determinant is non-zero, so the vectors are linearly independent. For this reason, we also know the dimension of is 3.
- Span:
Write an arbitrary vector in as
. Then the given vectors span
if there is always a choice of scalars
such that
which is equivalent to the system
The coefficient matrix is non-singular, so it has an inverse. Multiplying both sides by that inverse gives
so the vectors do span .
The vectors comprising form a basis for it because they are linearly independent.
Answer:
Step-by-step explanation:
<h3> The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle andLet be "s" the total number of seats in the Stalls.
The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is .
Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:
Solving for "s", we get:
So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:
We know that of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:
Therefore, the total number of seats that were occupied las Friday is:
Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:
Solving for "p", we get: