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boyakko [2]
2 years ago
10

Triangle J K L is shown. Angle K J L is 58 degrees and angle J L K is 38 degrees. The length of J K is 2.3 and the length of J L

is k.
Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

Which measures are accurate regarding triangle JKL? Select two options.

m∠K = 94°
k ≈ 3.7 units
k ≈ 4.6 units
KL ≈ 2.5 units
KL ≈ 3.2 units
Mathematics
2 answers:
Romashka-Z-Leto [24]2 years ago
5 0
Try 3.7 and see it u got it
yKpoI14uk [10]2 years ago
5 0

Answer:

C and D 3.7 and 2.5

Step-by-step explanation:

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ind the slope and y-intercept for the two linear functions. A 2-column table with 5 rows. Column 1 is labeled x with entries neg
Liula [17]

Answer:

-1/4

-4

3/2

1

got it right on edge 2020

Step-by-step explanation:

9 0
2 years ago
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Estimate the value of 50.75 x 0.18<br> Estimate the value of 196 divided by 0.499
DIA [1.3K]
<span>This question is a simple one. To answer this question, you need to understand the description in the question and determine to multiply or divide the number.

The first problem would be:
50.75 x 0.18= 9.135
</span>If you need to estimate, 50.75 is near 50; 0.18 is near 0.2 or 1/5 so it would be: 50/0.2= 10<span>

The second problem would be:
196 / 0.499: 392.785 
If you need to estimate, 0.499 is near 0.5 then 196/0.5 would be 392</span>
3 0
2 years ago
Read 2 more answers
Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
Debora [2.8K]

Option A

2x^2(6x-1) + 3(6x-1) is one way to determine the factors of 12x^3-2x^2+18x-3 by grouping

<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

12x^3-2x^2+18x-3

Group the first two terms together and then the last two terms together.

(12x^3-2x^2)+(18x-3)

We can see that 2x^2 is common in first two terms

And 3 is common in last two terms

Factor them out

(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)

2x^2(6x-1) + 3(6x-1)

Thus option A is correct

6 0
1 year ago
Read 2 more answers
The article "Expectation Analysis of the Probability of Failure for Water Supply Pipes"† proposed using the Poisson distribution
oksian1 [2.3K]

Answer:

a. P(X ≤ 5) = 0.999

b. P(X > λ+λ) = P(X > 2) = 0.080

Step-by-step explanation:

We model this randome variable with a Poisson distribution, with parameter λ=1.

We have to calculate, using this distribution, P(X ≤ 5).

The probability of k pipeline failures can be calculated with the following equation:

P(k)=\lambda^{k} \cdot e^{-\lambda}/k!=1^{k} \cdot e^{-1}/k!=e^{-1}/k!

Then, we can calculate P(X ≤ 5) as:

P(X\leq5)=P(0)+P(1)+P(2)+P(4)+P(5)\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\P(3)=1^{3} \cdot e^{-1}/3!=1*0.3679/6=0.061\\\\P(4)=1^{4} \cdot e^{-1}/4!=1*0.3679/24=0.015\\\\P(5)=1^{5} \cdot e^{-1}/5!=1*0.3679/120=0.003\\\\\\P(X\leq5)=0.368+0.368+0.184+0.061+0.015+0.003=0.999

The standard deviation of the Poisson deistribution is equal to its parameter λ=1, so the probability that X exceeds its mean value by more than one standard deviation (X>1+1=2) can be calculated as:

P(X>2)=1-(P(0)+P(1)+P(2))\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\\\P(X>2)=1-(0.368+0.368+0.184)=1-0.920=0.080

4 0
2 years ago
How do you use a number line to solve 235+123
Novosadov [1.4K]
<span>Number line refers to a mathematical process of solving the equation with the use of lines.
=> 235 + 123
Starting from 0 you count 1 up to 235. Then starting from 235 you additionally count another 123.
Then from zero start counting the total number to the line you stopped when adding 123 to 235.

This simply equals to
=> 235 + 123
=> 358.
Pls. see attached image for illustration of number line.</span>Answer here

6 0
2 years ago
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